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                                                                                                          8-3


                                                                                                        2
                                   Now the numerator of Equation S8-1 is a standard normal random variable. The ratio S    2  in
                                   the denominator is a chi-square random variable with n   1 degrees of freedom, divided by
                                   the number of degrees of freedom*. Furthermore, the two random variables in Equation
                                   S8-1, X  and  , are independent. We are now ready to state and prove the main result.
                                             S

                       Theorem S8-1:
                               The     Let Z be a standard normal random variable and V be a chi-square random variable with
                       t-Distribution
                                       k degrees of freedom. If Z and V are independent, the distribution of the random variable

                                                                          Z
                                                                    T
                                                                        2V k
                                       is the t-distribution with k degrees of freedom. The probability density function is

                                                        
 31k 	 12 24     1
                                                  f  1t2              2       1k	12  2  ,      t
                                                         2 k 
 1k 22 31t  k2 	 14



                                   Proof  Since Z and V are independent, their probability distribution is

                                                        v  1k  22 1  2
                                           f 1z, v2               e   1z 	 2  2 ,        z   , 0

                                                               k
                                           ZV
                                                          k  2

                                                    22  2 
 a b
                                                               2
                                   Define a new random variable U   V. Thus, the inverse solutions of
                                                                          z
                                                                     t
                                                                         1v k
                                   and

                                                                      u   v
                                   are
                                                                           u
                                                                     z   t
                                                                         A k
                                   and
                                                                     v   u


                                   The Jacobian is
                                                                     u    t       u
                                                               J   † A k  2uk †   A k
                                                                     0    1

                                   * We use the fact that 1n   12S    2  follows a chi-square distribution with n   1 degrees of freedom in Section 8-4
                                                       2
                                   to find a confidence interval on the variance and standard deviation of a normal distribution.
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