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                                                                                       10-4 PAIRED t-TEST  351


                                       3.  H :     0
                                               D
                                            1
                                       4.     0.05
                                       5.  The test statistic is
                                                                          d
                                                                    t
                                                                    0
                                                                        s D
 1n
                                       6.  Reject H if t 
 t 0.025,8    2.306 or if t   t 0.025,8    2.306.
                                                 0
                                                                         0
                                                     0
                                       7.  Computations: The sample average and standard deviation of the differences d are
                                                                                                          j
                                          d   0.2736 and s   0.1356, so the test statistic is
                                                        D
                                                                 d       0.2736
                                                          t                        6.05
                                                           0
                                                              s D
 1n  0.1356
 19
                                       8.  Conclusions: Since t   6.05 
 2.306, we conclude that the strength prediction
                                                            0
                                          methods yield different results. Specifically, the data indicate that the Karlsruhe
                                          method produces, on the average, higher strength predictions than does the Lehigh
                                          method. The P-value for t   6.05 is P   0.0002, so the test statistic is well into the
                                                               0
                                          critical region.

                                   Paired Versus Unpaired Comparisons
                                   In performing a comparative experiment, the investigator can sometimes choose between the
                                   paired experiment and the two-sample (or unpaired) experiment. If n measurements are to be
                                   made on each population, the two-sample t-statistic is
                                                                     X   X      0
                                                                           2
                                                                      1
                                                                T
                                                                 0
                                                                          1   1
                                                                       p
                                                                      S   B  n     n
                                   which would be compared to t 2n 2 , and of course, the paired t-statistic is

                                                                        D    0
                                                                   T 0
                                                                        S D
 1n

                                                        . Notice that since
                                   which is compared to t n 1
                                                   n D j   n 1X   X 2      n X 1j   n X 2j
                                                                     2j
                                                                1j
                                             D    a n      a      n         a n     a n     X 1    X 2



                                                  j 1      j 1             j 1      j 1
                                   the numerators of both statistics are identical. However, the denominator of the two-sample
                                   t-test is based on the assumption that X 1 and X 2 are independent. In many paired experiments,
                                   a strong positive correlation   exists between X 1 and X 2 . Then it can be shown that
                                                         V 1D2   V1X 1   X 2    0 2
                                                                V1X 1 2   V1X 2 2   2 cov 1X 1 , X 2 2
                                                                 2
                                                              2  11   2

                                                                  n
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