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               46     CHAPTER 2 PROBABILITY


               2-75.  The edge roughness of slit paper products increases as  (b) Find the probability that an incoming call is a request for
               knife blades wear. Only 1% of products slit with new blades  purchasing more products.
               have rough edges, 3% of products slit with blades of average  2-78.  Computer keyboard failures are due to faulty electri-
               sharpness exhibit roughness, and 5% of products slit with  cal connects (12%) or mechanical defects (88%). Mechanical
               worn blades exhibit roughness. If 25% of the blades in manu-  defects are related to loose keys (27%) or improper assembly
               facturing are new, 60% are of average sharpness, and 15% are  (73%). Electrical connect defects are caused by defective
               worn, what is the proportion of products that exhibit edge  wires (35%), improper connections (13%), or poorly welded
               roughness?                                      wires (52%).
               2-76.  Samples of laboratory glass are in small, light pack-  (a) Find the probability that a failure is due to loose keys.
               aging or heavy, large packaging. Suppose that 2 and 1% of  (b) Find the probability that a failure is due to improperly
               the sample shipped in small and large packages, respec-  connected or poorly welded wires.
               tively, break during transit. If 60% of the samples are  2-79.  A batch of 25 injection-molded parts contains 5 that
               shipped in large packages and 40% are shipped in small  have suffered excessive shrinkage.
               packages, what proportion of samples break during  (a) If two parts are selected at random, and without replace-
               shipment?                                          ment, what is the probability that the second part selected
               2-77.  Incoming calls to a customer service center are classi-  is one with excessive shrinkage?
               fied as complaints (75% of call) or requests for information  (b) If three parts are selected at random, and without replace-
               (25% of calls). Of the complaints, 40% deal with computer  ment, what is the probability that the third part selected is
               equipment that does not respond and 57% deal with  one with excessive shrinkage?
               incomplete software installation; and in the remaining 3% of  2-80.  A lot of 100 semiconductor chips contains 20 that are
               complaints the user has improperly followed the installation  defective.
               instructions. The requests for information are evenly divided  (a) Two are selected, at random, without replacement, from
               on technical questions (50%) and requests to purchase more  the lot. Determine the probability that the second chip se-
               products (50%).                                    lected is defective.
               (a) What is the probability that an incoming call to the cus-  (b) Three are selected, at random, without replacement,
                  tomer service center will be from a customer who has not  from the lot. Determine the probability that all are
                  followed installation instructions properly?    defective.




               2-6  INDEPENDENCE

                                 In some cases, the conditional probability of P1B ƒ A2  might equal P(B). In this special case,
                                 knowledge that the outcome of the experiment is in event A does not affect the probability that
                                 the outcome is in event B.


               EXAMPLE 2-23      Suppose a day’s production of 850 manufactured parts contains 50 parts that do not meet
                                 customer requirements. Suppose two parts are selected from the batch, but the first part is
                                 replaced before the second part is selected. What is the probability that the second part is
                                 defective (denoted as B) given that the first part is defective (denoted as A)? The probability
                                 needed can be expressed as P1B ƒ A2.
                                    Because the first part is replaced prior to selecting the second part, the batch still contains
                                 850 parts, of which 50 are defective. Therefore, the probability of B does not depend on
                                 whether or not the first part was defective. That is,

                                                               P1B ƒ A2   50
850

                                 Also, the probability that both parts are defective is

                                                                         50     50
                                                P1A ¨ B2   P1B 0 A2P1A2   a  b   a  b   0.0035
                                                                        850     850
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