Page 146 - Basic Well Log Analysis for Geologist
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LITHOLOGY  LOGGING  AND  MAPPING  TECHNIQUES






















        Figure  49.   Example  gamma  ray  log  depicting  a  20  API  unit  gamma  ray  cutoff  used  to  determine  a  clean  carbonate  interval.
               Given:   The  volume  of  shale  (V,,)  cutoff  is  arbitrarily  set  at  5%  (V,,  =  0.05).  Next,  determine  the  garnma  ray  index  from
                       the  chart  in  Figure  38;  Chapter  V  (gamma  ray  index  where  V,,  =  5%.  is  Igrz  =  0.10).
               Procedure:
                       1.  Determine  gamma  ray cutoff  (see  log;  and  Fig.  38).

                         Remember:
                           Igr  = See   SR
                                  Rinax  ~  GRnin
                         Where:
                           GRiog  =  gamma  ray  log
                           GRyax  =  gamma  ray  maximum  (shale)
                           GRypin  =  gamma  ray  minimum  (shale-free  sandstone  or  carbonate)
                         From  Log:
                           GRyax  =  90  (from  shale  zone  on  log)
                           GRmin  =  12  (from  clean  carbonate  zone  on  log)
                           Iga  =  0.10  (gr  for  Vn  =  0.05;  given)
                         Then:

                              _   GR,   —  GRnin
                           Icr  ~  AB
                                 GRinax  ~  GRain
                         Or:

                           0.10  =   Ree   —~  12  12
                                   90  —  12
                         Therefore:

                           GRjog  =  19.8  (round  off  to  20  API  units)
                      2   20  API  represents  clean  carbonate  where  the  volume  of  shale  is  equal  to  (or  less  than)  5%.
                         Draw  a  vertical  line  from  the  scale  value  of  20  API  units  and  determine  the  thickness  and  limits  of  the  clean
                         carbonate  formation  (bioherm)  much  as  you  determined  alpha  values  in  Figure  48.














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