Page 19 - Basic physical chemistry for the atmospheric sciences
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Chemical equilibrium                   5

                                    [N2(g)] = 0 . 18 M
              At  25°C  the  value  of Kc  for  Reaction  (l.7) i s   only  l x 1 0 -3o!  This
            implies  that  the  equilibrium  concentration  of NO(g)  is  very  low  at
            normal  temperatures  and  that  the  equilibrium  "lies  to  the  left"  of
            Reaction  (l .7),  favoring  the  reactants.  Hence,  in  the  troposphere,
                                                              (
            negligible quantities of NO(g) are produced by Reaction  1 .7).
              In the case of chemical  reactions  involving only gases,  it is  often
            more convenient to express the equilibrium constant for the reaction
            in terms of the partial pressures of the reactants and products instead
            of their molarities.  However,  before  doing this  we  must review  the
            ideal gas equation.
              Laboratory  experiments  show  that for a  wide  range of conditions
            the pressure  (p),  volume (V) and temperature (D of all gases follow
            closely the same relationship, which is called the ideal gas equation.
                                    I
            In  SI units (see Appendix  ) ,   the ideal gas equation can be written in
            the following forms. For mass m (in kilograms) of a gas
                                                                      l
                                       p V = mRT                     (  . 8a)
            where  p  is  in  pascal s ,    V  in  cubic  meters,  T  in  K  (K =
            °C + 273. 1 5   = °C + 273), and R is the gas constant for I kg of a gas. The
            value of R depends on the number of molecules in I kg of the ga ,   and
                                                                     s
            therefore varies from one gas to another. Since m/V = p, where p is the
            density of the gas,
                                        p=RpT                        ( I .Sb)

            For I  kg of gas (m = I), Eq. ( I .Sa) becomes

                                        pa =  R  T                   (l 8c)
                                                                       .
            where a  is the specific volume of the gas (i. e . , the volume occupied by
            1  kg of the gas).  One mole of any gas contains the same number of
            molecules (NA)·  Therefore, the gas constant for I  mole is the same for
            all  gases  and  is  called  the  universal  gas  constant  R*(8. 3 1 4 3  J  deg-1
                 1
            mol- ) .   Therefore,
                                       p V =  nR*T                   (l . 8d)
            where n is the number of moles of the gas, which is given by

                                          I O OOm
                                          --
                                       n=
                                            M
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