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8                   Basic physical chemistry
                        [0 (g)]      M
                                                       .
                          3      or         M-  I  ,  the umts of KP are
                     [O(g)][Oz(g)]   (M)(M)
                               Po,         atm
                             --- or               = a tm- 1 •
                             (p o)( Po,)   (atm)(atm)
            Nevertheless, it is common practice in chemistry not to indicate the
            units of equilibrium constants, with the understanding that when Kc is
            used  the  concentrations  are  in molarity,  and  when  KP  is  used  the
                                           s
            partial pressures are in atmosphere .
                                           i
              Exercise 1.4.  Ammonia, NH 3 (g),  s   produced commercially from the
                              n
                                                            n
            reaction of hydroge ,   Hi{g), and atmospheric nitroge ,   Nz(g),  at high
            temperatures.  If Hz(g),  N2(g),  and NH (g)  attain equilibrium at 472°C
                                               3
            when their concentrations are  0. 1 2   M,  0.04  M  ,   and 0.003  M,  respec­
            tively, calculate the values of Kc and K P  for the reaction at 472°C.
              Solution. The  balanced chemical equation for the reaction is


            Hence, from Eq.  (1.6)
                                                     2
                                                1 2
                          K =    [NH3(g)] 2    (0.003)    O
                            c  [ Hz(g)] [ N (g)]  (0.  ) (0.04)   .  l
                                    3
                                                  3
                                       2
            From Eq. ( 1 .9a)
                                    Kc= K P (R�T),J.n
                            �
            where Kc=O. l ,   R =0.0821  L atm deg- 1 mo1-1, T=745K and, from Eq.
            ( l .9c), �n=(3+  1)- (2)=2. Therefore,

                                       2 1 0.1
                                                       - '
                              K P =            -3xto  -
                                             5)
                                   (0.08  x7 4 2

                                  1.3  Reaction  quotient
            If  the  general  chemical  reaction  represented  by  Eq.  (1.5)  is  no�  in
            equilibrium,  we  can  still formulate a ratio of concentrations that has
            the same form as Eq.  1 . 6). This is called the reaction quotient,  Q
                                (
                                       =  [G]g[H]h .. .               ( l . 1 0 )
                                     Q [A]a[B]b .. .
            Clearly, if Q =Kc, the reaction is  in chemical equilibrium.  If Q  < Kc,
            the  reaction  is  not  in  equilibrium,  and  it will proceed in  the  forward
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