Page 259 - Biomass Gasification, Pyrolysis And Torrefaction Practical Design and Theory
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Chapter | 7  Gasification Theory                             235


             C, H, and O, or any other dominant elements. If other elements form a minor
             part of the product gas, they are often neglected.
                Let us take the example of 1 mol of biomass being gasified in d moles of
             steam and e moles of air. The reaction of the biomass with air (3.76 moles
             of nitrogen, 1 mol of oxygen) and steam may then be represented by:
                  CH a O b N c 1 dH 2 O 1 eðO 2 1 3:76N 2 Þ-n 1 C 1 n 2 H 2 1 n 3 CO
                                                                       (7.65)
                          1 n 4 H 2 O 1 n 5 CO 2 1 n 6 CH 4 1 n 7 N 2
             where n 1 , ..., n 7 are stoichiometric coefficients. Here, CH a O b N c is the chem-
             ical representation of the biomass and a, b, and c are the mole ratios (H/C,
             O/C, and N/C) determined from the ultimate analysis of the biomass. With d
             and e as input parameters, the total number of unknowns is seven.
                An atomic balance of carbon, hydrogen, oxygen, and nitrogen gives:
                                  C: n 1 1 n 3 1 n 5 1 n 6 5 1         (7.66)
                                  H:  2n 2 1 2n 4 1 4n 6 1 a 1 2d      (7.67)

                                  O: n 3 1 n 4 1 2n 5 5 b 1 d 1 2e     (7.68)
                                  N:  n 7 5 c 1 7:52e                  (7.69)
                During the gasification process, reactions R1, R2, R3, and R9 (see
             Table 7.2) take place. The water gas shift reaction, R9, can be considered a
             result of the subtraction of the steam gasification and Boudouard reactions,
             so we consider the equilibrium of reactions R1, R2, and R3 alone. For a gas-
             ifier pressure, P, the equilibrium constants for reactions R 1 ,R 2 , and R 3 are
             given by:
                                           y 2  P
                                        5   CO   R1                    (7.70)
                                     K e 1
                                           y CO 2
                                               P
                                       5          R2                   (7.71)
                                         y CO y H 2
                                    K e 2
                                           y H 2 O
                                         5  y CH 4  R3                 (7.72)
                                      K e 3  2
                                           y P
                                            H 2
             where y i is the mole fraction for species i of CO, H 2 ,H 2 O, and CO 2 .
                The two sets of equations (stoichiometric and equilibrium) may be solved
             simultaneously to find the coefficients, (n 1 , ..., n 7 ), and hence the product
             gas composition in an equilibrium state. Thus, by solving seven equations
             (Eqs. (7.66) (7.72)) we can find seven unknowns (n 1 , ... ,n 7 ), which give
             both the yield and the product of the gasification for a given air/steam-to-
             biomass ratio. The approach is based on the simplified reaction path and the
             chemical formula of the biomass.
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