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Transcendental Functions
                     CHAPTER 6
                        Notice that when the number of bacteria is large, then different generations of  173
                     bacteria will be reproducing at different times. So, averaging out, it makes sense
                     to hypothesize that the growth of the bacteria population varies continuously as
                     in Fig. 6.13. Here we are using a standard device of mathematical analysis: even
                     though the number of bacteria is always an integer, we represent the graph of the
                     population of bacteria by a smooth curve. This enables us to apply the tools of
                     calculus to the problem.

















                                                    Fig. 6.13


                     6.5.1     A DIFFERENTIAL EQUATION

                     If B(t) represents the number of bacteria present in a given population at time t,
                     then the preceding discussion suggests that
                                                  dB
                                                     = K · B(t),
                                                  dt
                     where K is a constant of proportionality. This equation expresses quantitatively
                     the assertion that the rate of change of B(t) (that is to say, the quantity dB/dt)is
                     proportional to B(t). To solve this equation, we rewrite it as

                                                   1    dB
                                                      ·    = K.
                                                  B(t)  dt
                     We integrate both sides with respect to the variable t:

                                                 1   dB
                                                    ·    dt =   Kdt.
                                               B(t)   dt
                     The left side is
                                                   ln |B(t)|+ C

                     and the right side is
                                                     Kt + C,
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