Page 99 - Calculus Workbook For Dummies
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83
                                               Chapter 6: Rules, Rules, Rules: The Differentiation Handbook



                    i    d  _ x  3 cosx =  3 x  2  cosx -  x  3  sinx
                                   i
                         dx
                                       d
                         Remember that   cosx = - sinx. For a great mnemonic to remember the derivatives of trig
                                       dx
                         functions, check out Chapter 15.
                             d   3         3 l         3  cosx l
                                                  h
                            dx _ x  cosx = _i  x i  ^ cosx + _ x ^ i  h
                                                   3
                                       =  3 x  2  cosx +  x - sinxh
                                                    ^
                                       =  3 x  2  cosx -  x  3 sinx
                    j    d  ^ sin tanx =  cos tanx +  sec tanx
                                                     x
                               x
                                          x
                                    h
                         dx
                                      d          2
                         A helpful rule:   tanx =  sec x.
                                      dx
                             d  ^ sin tanx = ^h  sinx l ^ tanx + ^h  sinx ^h  tanx l
                                  x
                                                                  h
                                               h
                            dx
                                                           2
                                             x
                                                       x
                                         =  cos tanx +  sin sec x
                                                        x
                                             x
                                         =  cos tanx +  sec tanx
                         d
                    k    dx  5 x  3  lnx =  5 x 3  lnx +  1h
                                      2
                                      ^
                                            d      1
                         Another helpful rule:   lnx =  . As for the 5, you can deal with it in two ways. First, you can
                                           dx      x
                         ignore it temporarily (because coefficients have no effect on differentiation), and put it back
                         when you’re done differentiating. If you do it this way, don’t forget that the “5” multiplies the
                         entire derivative, not just the first term. The second way is probably easier and better: just
                         make the “5” part of the first function. To wit:
                             d  5 x  3 lnx = _i  5 x i  lnx + _ 5 x ^ i  lnx l
                                           3 l
                                                       3
                            dx _             ^   h          h
                                                   3
                                       =  15 x  2  lnx +  5 x $  1
                                                     x
                                       =  15 x  2  lnx +  5 x  2  or
                                           2
                                       =  5 x 3 ^  lnx +  1h ; take your pick.
                   *l    d  x e  x  lnx =  e  x  lnx x +  2 i  xe  x
                             2
                                            2
                                                x +
                                          _
                         dx
                         This is a challenge problem because, as you’ve probably noticed, there are three functions
                         in this product instead of two. But it’s a piece o’ cake. Just make it two functions: either
                           2  x          2   x
                         _ x e ^ i  lnxh  or _ x _i  e  lnxi. Take your pick.
                                     d   x  x           x                     x
                         A handy rule:   e =  e (Note that e and its multiples (like 4e ) are the only functions that are
                                     dx
                         their own derivatives.)
                         1. Rewrite this “triple function” as the product of two functions.
                              d   2  x
                            =   _ x e ^ i  lnxh
                              dx
                         2. Apply the product rule.
                             d   2  x        2  x l       2  x  lnx l
                                                     h
                                        h
                            dx _ x e ^ i  lnx = _ x e i  ^ lnx + _ x e ^ i  h
                                                               x l
                                                             2
                         3. Apply the product rule separately to  x e i , then substitute the answer back where it
                                                           _
                           belongs.
                              2  x l  2 l  x    2  x l
                            _ x e i  = _ x i  _ e i  + _ x _i  e i
                                       x
                                           2
                                  =  2 xe +  x e  x
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