Page 133 - Chemical equilibria Volume 4
P. 133

Determination of the Values Associated with Reactions – Equilibrium Calculations     109
                                                1
                                 =
                                               −
                                             1
                              0
                                            −
                                   7.60 J.mol K ;
                           Δ s – standard entropy of  vaporization of liquid copper at 298 K:
                              298
                            V
                                                                                     -1
                             – enthalpy of fusion of copper at 1357 K: Δ Fh 1357 = 741.6 J.mol
                             – specific heat capacity of solid copper at constant pressure:
                                                            −
                                                               −
                                           +
                                                   −
                                                                1
                                                    3
                                                             1
                                 C P (sol)  = 1.30 3.52.10 T  J.mol K
                             – specific heat capacity of liquid copper at constant pressure, independent
                           of the temperature:
                                                −
                                                   −
                                                    1
                                                 1
                                 C P (liq)  = 1.79 J.mol K
                             – specific heat capacity of copper vapor at constant pressure, independent
                           of the temperature:
                                                  −
                                                   1
                                 C P (vap )  =  1.189 J.mol K − 1
                             We shall express the term   Δ (sublim) C = C (vap)  − C P (sol)   between 298 and
                                                               P
                                                                    P
                           1357 K:
                                                          −
                                                           3
                                                  −
                                 Δ (sublim) C =− 0.111 3.52.10 T
                                        P
                             Let us express the term   Δ C =  C (vap )  −  C P (l )  between 1357 K and
                                                                       i
                                                                        q
                                                         v
                                                           P
                                                                P
                           temperature T:
                                 Δ C =−  0.605 J.mol K  − 1
                                                   1
                                  v
                                    P
                             The standard enthalpy at T will be given by:
                                              1357                  T
                                                    ol
                                 Δ  v T 0  Δ h =  v 298 ∫  h 0  +  (s )  dT + ΔC  F 1357 ∫  +  Δ h  v C P  dT
                                                   P
                                               298                 1357
                             Thus, when  we feed the specific  heat capacities  and the enthalpy of
                           fusion back into this formula, we obtain:
                                          1357                               T
                            Δ  v T 0  Δ h =  v 298 ∫  h 0  +  ( 0.111 3.52.10 T−  −  − 3  ) dT + 741.6 −  ∫  0.605dT
                                           298                              1357
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