Page 134 - Chemical equilibria Volume 4
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110     Chemical Equilibria
                             This gives us the expression:
                                 Δ h = 11858 0.065T
                                             −
                                    0
                                  v T
                             Similarly, the standard entropy at T will be given by:
                                              1357 C (s )           T  Δ C
                                                    ol
                                                            F 1357 ∫
                                 Δ  v T 0  Δ s =  v 298 ∫  s 0  +  P  dT + Δ s  +  v  dT
                                               298  T              1357  T  P
                             By feeding the values of the specific heat capacities into this equation, we
                           find:

                                          1357 ( 0.111 3.52.10 T−  −  − 3  )  741.6  T  0.605
                            Δ  v T 0  Δ s =  v 298 ∫  s 0  +     dT +      −  ∫      dT
                                          298         T               1357   1357  T
                             This expression can be simplified to:

                                    0
                                 Δ s =  761 0.605 lnT
                                          −
                                  v T
                             Ultimately, the standard Gibbs energy is:
                                                  s =
                                                           −
                                                                          T
                                 Δ  v  0 T  Δ g =  v T 0  T  Δh −  v T 0  11858 760.9T + 0.605 lnT
                             This gives us a value for the saturating vapor pressure, expressed in bars,
                           which is the equilibrium constant of the vaporization reaction:


                                                                +
                                                    v
                                 ln P (vap )  =  ln K (I)  = −  Δ g T 0  = − 91.45 0.072lnT − 1425
                                    Cu
                                                   RT                         T
                             As we can see, the expressions with which we are working here can
                           quickly become rather  complex,  which is  why it is so helpful to use
                           computer technology to perform the calculations.


                           4.2. Enthalpies of reaction – thermochemistry

                             We know that  the reaction enthalpy is identical to  the  reaction  heat  at
                           constant pressure.  The properties  and  means of determining these  reaction
                           heats make up hermochemistry.
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