Page 185 - Chemical equilibria Volume 4
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As this property is extensive, it has corresponding partial molar values,
                           relating to each component of the solution, defined by:   Appendix 1     161
                                      ⎛  J ⎞ ∂  xs
                                 J  xs  =  ⎜  ⎟                                         [A1.26]
                                      ⎝  n ∂  i ⎠  PT n
                                             ,, j i≠

                             We can divide this definition for the Gibbs energy.



                           A1.3.2. Excess Gibbs energy

                             Consider a  solution. The excess  Gibbs energy, according to the
                           definition, will be:


                                        −
                                 G =  G G  *                                            [A1.27]
                                  xs
                             However, the molar Gibbs energy of the solution can be written:

                                      N       N
                                  m ∑
                                 G =    x μ i ∑  =  ⎣  x ⎡  i  ( g + Rln x + R lnγ (I) ) ⎤  ⎦  [A1.28]
                                                     0
                                                                   T
                                                          T
                                                               i
                                                     i
                                         i
                                                                        i
                                      i= 1    i= 1
                             Similarly, for a perfect solution, this molar Gibbs energy would be:
                                  m ∑
                                 G =  N  ⎣  x ⎡  i ( g +  Rln x ⎤  T  i ) ⎦             [A1.29]
                                             0
                                  *
                                             i
                                      i= 1
                             From this, we deduce the molar excess Gibbs energy of the solution at
                           hand:
                                          N
                                 G =  RT ∑  x i  lnγ i (I)                              [A1.30]
                                  xs
                                  m
                                         i= 1
                             If the excess Gibbs energy is known, the solution is completely
                           characterized: if we add the term of the Gibbs energy of the perfect solution,
                           we obtain the Gibbs energy of the solution, which is the characteristic
                           function with our choice of variables P, T and composition.
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