Page 42 - Chemical equilibria Volume 4
P. 42

18     Chemical Equilibria
                             However, the differential of the partial molar enthalpy can be expressed
                           in the form:
                                 d H = T d S + V  k  d P + ∑ μ k  d n k                  [1.75]
                                    k
                                           k
                                                       k
                             Thus, at a given pressure and extent, we obtain:
                                 ⎛  H k ⎞ ∂  ⎛  k S ⎞ ∂
                                 ⎜    ⎟  =  T ⎜   ⎟  = C  k P                            [1.76]
                                 ⎝  ∂ T  j P ⎠  ⎝  ∂ T  j P ⎠

                             By substituting that equation back into relation [1.74], we find:


                                 ⎛ ∂ Q P ⎞
                                 ⎜    ⎟  =  ∑ν k C P =  Δ r C P                          [1.77]
                                 ⎝  ∂ T  P ⎠  k  k

                             This relation constitutes what we  call the  Kirchhoff relation. An
                           equivalent relation would give the variation of the heat of transformation at
                           constant volume with the temperature as a function of the molar specific heat
                           capacity at constant volume associated with the transformation.



                           1.6. Set of points representing the equilibrium states of a
                           transformation

                             Consider a transformation at thermodynamic equilibrium for given values
                           of the variables of state. Its affinity is null. If we vary one or more of the
                           variables of  state by an infinitesimal  amount, the  affinity takes on a new
                           value A  + d A . In order for that new state to also be a state of equilibrium of
                           transformation, it is necessary for that new value of the affinity to be null,
                           so:

                                 A  +  d A  =  0                                         [1.78]

                             This leads us to:

                                 d A  =  0                                               [1.79]
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