Page 39 - Chemical equilibria Volume 4
P. 39

1.5.1.  Heat of transformation at constant pressure and
                           temperature                  Physico-Chemical Transformations and Equilibria     15
                             We can express the elementary heat of a transformation in the form:
                                δ Q = T  d S = T  d S T d S                              [1.57]
                                                  −
                                        e
                                                      i
                             By choosing all the variables (T, -P, ξ), we shall have:

                                         S ∂      S ∂       S ∂
                                    =
                                δ QT      dT T+     d P T+   dξ − T d S                  [1.58]
                                       ∂ T       ∂ P       ξ ∂       i
                             At constant pressure and temperature, this gives us:

                                         S ∂
                                δ Q = T    dξ − T  d S                                   [1.59]
                                   P
                                         ξ ∂       i

                             However, as the generalized Gibbs energy Γ  is a function of state, we
                           have, according to relation [1.19]:

                                 ⎛  S ⎞ ∂  ⎛  ∂ ⎞ A
                                 ⎜   ⎟  =− ⎜    ⎟                                        [1.60]
                                 ⎝  ∂ξ ⎠  , PT  ⎝  ∂ T  , P ⎠  ξ

                             Thus, we can write relation [1.59] in the form:

                                        ⎡  ⎛  ∂ ⎞ A   ⎤
                                δ Q =− ⎢  P  T  ⎟  + A ⎥ ⎜  dξ                           [1.61]
                                           ⎝ ⎢  ∂ T  , P ⎠  ξ  ⎥ ⎣  ⎦

                             By integrating this expression for the  whole of the transformation, we
                           obtain:

                                     ξ =∞       ⎡  ⎛  ∂ ⎞ A   ⎤
                                 Q =  ∫  δ Q = − ⎢  P  T  ⎟  + A ⎥ ⎜                     [1.62]
                                  P
                                     ξ = 0        ⎝ ⎢  ∂ T  , P ⎠  ξ  ⎥ ⎣  ⎦

                             By replacing the affinity with its expression [1.22], we find:


                                 Q = T ∑  ν k  ∂ μ k  + ∑  νμ k                          [1.63]
                                  P
                                                     k
                                        k   ∂ T   k
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