Page 123 - Circuit Analysis II with MATLAB Applications
P. 123

Properties of the Laplace Transform


         Using integration by parts where


                                              d
                                                          d
                                            ³ vu =  uv – ³ u v                                 (4.17)
         we let du =  f ' t    and v =  e – st . Then, u =  f t   , dv =  – se – st , and thus


                                             +
                                               s
                          ^
                        Lf ' t   `  =  ft  e – st  f   ³  f  f t  e – st dt =  lim  ft  e – st  a  +  sF s
                                           0     0             a o  f       0
                                 =  lim  e >  – sa fa    f0    –     @  +  sF s   =  0  f 0    –     +  sF s
                                    a o  f
         The time differentiation property can be extended to show that


                                     d 2        2
                                    -------- ft   œ  s Fs   –  sf 0      f ' 0     –           (4.18)
                                    dt  2


                                d  3
                                                   2
                                           3
                               -------- ft   œ  s Fs   –  s f0      sf ' 0     –  f '' 0     –  (4.19)
                               dt  3
         and in general


                         d  n       n        n –  1     n2              n1
                                                                         –
                                                         –
                         -------- ft   œ  s Fs   –  s  f0      –  s  f ' 0      –  } –  f  0       (4.20)
                         dt  n
         To prove (4.18), we let
                                                            d
                                             gt   =  f ' t   =  ----- ft
                                                           dt
         and as we found above,

                                                        ^ =
                                        L g ' t   `   sL g t   –  g0
                                                             `

                                           ^
         Then,
                                          ^ =
                          L f '' t   `  sL f ' t   –  f ' 0         =  ssL f t   @  f0    –     @  f ' 0     –
                                                                >
                             ^
                                                            >
                                               `
                                        2
                                    =  s Fs   –  sf 0         f ' 0     –
         Relations (4.19) and (4.20) can be proved by similar procedures.
         We must remember that the terms f 0        f ' 0           f '' 0           , and so on, represent the initial conditions.
                                                                                               times,
         Therefore, when all initial conditions are zero, and we differentiate a time function f t   n
                                              s
         this corresponds to Fs    multiplied by   to the nth  power.





        Circuit Analysis II with MATLAB Applications                                              4-5
        Orchard Publications
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