Page 123 - Civil Engineering Formulas
P. 123

66                      CHAPTER TWO

                           F                   F


                                      h o  e
                                               +y
                       a
                              h i

                            Neutral
                            surface         R
                                         R i
                                           R o
                     F                                F
                FIGURE 2.21  Curved beam.


           R is the radius of the centroidal axis; Z is a cross-section property defined
           by
                               Z           y
                                     1
                                     A   R   y  dA              (2.19)

             Analytical expressions for Z of certain sections are given in Table 2.4. Z can
           also be found by  graphical integration methods (see any advanced strength
           book). The neutral surface shifts toward the center of curvature, or inside fiber,
           an amount equal to e   ZR/(Z   1). The Winkler-Bach theory, though practi-
           cally satisfactory, disregards radial stresses as well as lateral deformations and
           assumes pure bending. The maximum stress occurring on the inside fiber is
           S   Mh i /AeR i , whereas that on the outside fiber is S   Mh o /AeR o .
             The deflection in curved beams can be computed by means of the moment-
           area theory.
                                                   2    2
             The resultant deflection is then equal to   0      x    y  in the direction
           defined by tan     y /   x .  Deflections can also be found conveniently by use
           of Castigliano’s theorem. It states that in an elastic system the displacement in
           the direction of a force (or couple) and due to that force (or couple) is the partial
           derivative of the strain energy with respect to the force (or couple).
             A quadrant of radius R is fixed at one end as shown in Fig. 2.22. The force F
           is applied in the radial direction at free-end B. Then, the deflection of B is
           By moment area,

                             y   R sin    x   R(1   cos  )      (2.20)
                             ds   Rd   M   FR sin               (2.21)

                                 
FR 3          FR 3
                            B   x        B   y                  (2.22)
                                  4EI           2EI
   118   119   120   121   122   123   124   125   126   127   128