Page 56 - Civil Engineering Formulas

WL 3 EI (L 2 – 2Lx + x 2 )

1 384 EIL
D (max) = Wx 2 D = 24

At center: x: At

CASE 5. Beam Fixed Both Ends—Continuous Load, Uniformly Distributed

D M M 1 V
Lx – x 2 R 1

WL 24 WL 12 L 2 – + 6
M (max) = M 1 (max) = W = 2L L W

At center: At supports: x: At M R x V

W 2
R = R 1 = V (max) = Wx W – V = L 2

x:
At

24