CASE 7. Beam Fixed at One End (Cantilever)—Continuous Load, Uniformly Distributed
At free end:
M (max) = WL 3 WL D (max) = 8EI 2 x: At Wx 2 W M = (x 4 – 4L 3 x + 3L 4 ) D = 2L 24EIL L W R 1 Loading M Bending V Shear
At fixed end: x: At D x
R 1 = V (max) = W x: At Wx V = L
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