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CASE 10. Beam Fixed at One End, Supported at Other—Continuous Load, Uniformly Distributed
3 L 8 x: when x = 0.4215L At 9 WL 3 WL D (max) = 0.0054 128 EI 1 x: At WL M 1 (max) = Wx 8 – 3Lx 2 + 2x 3 + L 3 D = 48EIL 1 3 Wx x L – 2 8 L L W R 1 M M 1 V
x: when x = M (max) = At fixed end: = M x
At x: At D R
W
5 8 Wx L
R 1 = V (max) =
W – W (Continued)
3 8 3 8
R = V =
x: FIGURE 2.2
At
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