Page 67 - Civil Engineering Formulas

CASE 11. Beam Overhanging Both Supported Unsymmetrically Placed—Continuous Load, Uniformly Distributed
R a – w R a – (max) = R 2w 1 wa 2 = 2 1 wb 2 1 x) 2 – (a w = M 2 1 Rx 1 – x 1) 2 + (a w = M 2 1 x 2 ) 2 – (b w = M 2 W b L R 1 R x 2 xx 1 M M1
x 1 : when x 1 = M M1 M1 = x: when x < a 2 x 1: when x 1 < L x 2: when x 2 < b a M 1

At R: At R1: At At At At
= load per unit of length [(a + L) 2 + b 2 ] 2L [(b + L) 2 + a 2 ] 2L (a + x 1)

W R = w R 1 = w (max) = wa or R – wa x: when x < a V = w (a – x) x 1 : when x 1 < L V = R – w x 2 : when x 2 < b V = w(b – x 2 )
=
L + b
W V
+ At At At
a

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