Page 75 - Classification Parameter Estimation & State Estimation An Engg Approach Using MATLAB
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64                                       PARAMETER ESTIMATION

              The overall bias must be considered as an average taken over the full
            range of x. To see this, rewrite p(x,z) ¼ p(zjx)p(x) to yield:

                                        Z
                                    b ¼   bðxÞpðxÞdx                   ð3:37Þ


            where b(x) is given in (3.35).
              If the overall bias of an estimator is zero, then the estimator is said to
            be unbiased. Suppose that in two different areas of x the biases of an
            estimator have opposite sign, then these two opposite biases may cancel
            out. We conclude that, even if an estimator is unbiased (i.e. its overall
            bias is zero), then this does not imply that the bias for a specific value of
            x is zero. Estimators that are unbiased for every x are called absolutely
            unbiased.
              The variance of the error, which serves to quantify the random fluc-
            tuations, follows the same line of reasoning as the one of the bias. First
            we determine the covariance matrix of the error with non-random x:

                     def  h                T  i
                C e ðxÞ¼E ðe   E½eŠÞðe   E½eŠÞ jx
                        Z                                              ð3:38Þ
                                                         T
                           x
                                           x
                      ¼   ð^ xðzÞ  x   bðxÞÞð^ xðzÞ  x   bðxÞÞ pðzjxÞdz
            As before, the integral extends over the full space of z. The variances of
            the elements of e are at the diagonal of C e (x).
              The magnitude of the full error (bias þ random part) is quantified by
            the so-called mean square error (the second order moment matrix of the
            error):

                                     T
                               def
                         M e ðxÞ¼Eee jx
                                                                       ð3:39Þ
                                  Z
                                                      T
                                     x
                                              x
                                ¼   ð^ xðzÞ  xÞð^ xðzÞ  xÞ pðzjxÞdz
            It is straightforward to prove that:
                                             T
                                M e ðxÞ¼ bðxÞb ðxÞþ C e ðxÞ            ð3:40Þ

            This expression underlines the fact that the error is composed of a bias
            and a random part.
              The overall mean square error M e is found by averaging M e (x) over all
            possible values of x:
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