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8.4 Generating Functions  541


                                                                                                     −n
                                                     Using Example 8, which provides a simple formula for  , we obtain
                                                                                                     k
                                                                    ∞

                                                                           k
                                                                                           k
                                                        (1 + x) −n  =  (−1) C(n + k − 1,k)x .
                                                                    k = 0
                                                     Replacing x by −x, we find that


                                                                    ∞

                                                               −n                     k
                                                        (1 − x)  =     C(n + k − 1,k)x .
                                                                    k = 0                                                           ▲
                                                        Table 1 presents a useful summary of some generating functions that arise frequently.

                                                     Remark: Note that the second and third formulae in this table can be deduced from the first
                                                                                r
                                                     formula by substituting ax and x for x, respectively. Similarly, the sixth and seventh formulae
                                                     can be deduced from the fifth formula using the same substitutions. The tenth and eleventh can
                                                     be deduced from the ninth formula by substituting −x and ax for x, respectively. Also, some
                                                     of the formulae in this table can be derived from other formulae using methods from calculus
                                                     (such as differentiation and integration). Students are encouraged to know the core formulae in
                                                     this table (that is, formulae from which the others can be derived, perhaps the first, fourth, fifth,
                                                     eighth, ninth, twelfth, and thirteenth formulae) and understand how to derive the other formulae
                                                     from these core formulae.



                                                     Counting Problems and Generating Functions

                                                     Generating functions can be used to solve a wide variety of counting problems. In particular, they
                                                     can be used to count the number of combinations of various types. In Chapter 6 we developed
                                                     techniques to count the r-combinations from a set with n elements when repetition is allowed
                                                     and additional constraints may exist. Such problems are equivalent to counting the solutions to
                                                     equations of the form


                                                        e 1 + e 2 + ··· + e n = C,

                                                     where C is a constant and each e i is a nonnegative integer that may be subject to a specified
                                                     constraint. Generating functions can also be used to solve counting problems of this type, as
                                                     Examples 10–12 show.

                                     EXAMPLE 10      Find the number of solutions of


                                                        e 1 + e 2 + e 3 = 17,

                                                     where e 1 ,e 2 , and e 3 are nonnegative integers with 2 ≤ e 1 ≤ 5, 3 ≤ e 2 ≤ 6, and 4 ≤ e 3 ≤ 7.

                                                     Solution: The number of solutions with the indicated constraints is the coefficient of x 17  in the
                                                     expansion of

                                                          2
                                                                                                  5
                                                                                             4
                                                                                                      6
                                                                                                           7
                                                               3
                                                                                4
                                                                            3
                                                                        5
                                                                   4
                                                                                          6
                                                                                     5
                                                        (x + x + x + x )(x + x + x + x )(x + x + x + x ).
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