Page 234 - Design of Reinforced Masonry Structures
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DESIGN OF REINFORCED MASONRY BEAMS          4.97



                                                                     2'-8"




                                           Lintel                    4'-8"





                                        Opening                      4'-0"


                                      5'-4" (Clear)
                                                                     4'-0"



               FIGURE E4.27A   Design of a lintel.



           a.  Analysis of loads on lintel
             Calculate the depth of lintel adequate to carry shear without shear reinforcement.
                               Clear span (width of opening),
                                   L = 5 ft 4 in. = 5.33 ft
             Length of bearings on each side of lintel = 8 in. = 0.67 ft
                                     Effective span,
                                  L  = 5.33 + 0.67 = 6 ft
                                   e
             Assume depth of lintel, d = 8 in. (to be revised later if necessary)
                           Height of parapet = 2 ft 8 in. = 2.67 ft
                   Height of masonry above the top of lintel = 4 + 2.67 = 6.67 ft
              Height of wall required above the top of lintel to develop arching action =
                            L 2 e  + 8 in. =  6  +  067 367 ft  <  667 ft
                                          =
                                                   .
                                       .
                                            .
                                    2
             Hence there is sufficient masonry wall depth above the lintel and arching action
           can be assumed to exist. The superimposed concentrated loads are applied at a height
           of 4 ft above the top of lintel, which is 4 in. (4 − 3.67 = 0.33 ft = 4 in.) above the apex
           of the 45° traingle; therefore, these loads would disperse through arching action at an
           angle of 60°.
             Calculate the weight of masonry, W, contained in the 45° triangle with base equal to
                                                    2
           6 ft (Fig. E4.27B). The unit weight of masonry is 78 lb/ft  of wall (Table A.19). Thus,
                                 1     1
                             W =  wL =  ( 78 6)  2  = 702 lb
                                    2
                                           (
                                           )
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