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222   5. Further Determinant Theory

            Applying Taylor’s theorem again,
                                             ∞   2n+1  2n+1
                                                z    D     (φ)
                      1 {φ(x + z) − φ(x − z)} =               ,
                      2                            (2n + 1)!
                                             n=0
                                             ∞
                                                     2n
                                                 2n
                                                z D (ψ)
                     1
                     2  {ψ(x + z)+ ψ(x − z)} =     (2n)!  .          (5.7.2)
                                             n=0
          5.7.2  A Determinantal Identity
          Define functions φ, ψ, u n and a Hessenbergian E n as follows:
                                     φ = log(fg),
                                     ψ = log(f/g)                    (5.7.3)
                                   u 2n = D (φ),
                                           2n
                                 u 2n+1 = D 2n+1 (ψ),                (5.7.4)
                                    E n = |e ij | n ,
          where
                              
                                  j − 1
                                        u j−i+1 ,j ≥ i,
                                  i − 1
                              
                         e ij =                                      (5.7.5)
                               −1,              j = i − 1,
                              
                                0,               otherwise.
          It follows from (5.7.3) that
                                    f = e (φ+ψ)/2 ,
                                     g = e (φ−ψ)/2 ,
                                   fg = e .                          (5.7.6)
                                         φ
          Theorem.
              H (f, g)
               n
                fg    = E n

                          u 1  u 2  u 3  u 4  ··· u n−1
                                                       	    u n
                                                        n − 1

                          −1  u 1  2u 2  3u 3  ···  ···

                                                        n − 2  u n−1


                                                        n − 1

                             −1    u 1  3u 2  ···  ···         u n−2   .

                                                        n − 3
                      =

                                  −1        ···  ···        ···

                                        u 1

                                            ···  ···        ···

                                                 −1         u 1

                                                                    n
            This identity was conjectured by one of the authors and proved by Cau-
          drey in 1984. The correspondence was private. Two proofs are given below.
          The first is essentially Caudrey’s but with additional detail.
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