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Chapter 11 – WELL CONTROL                                        271








                    This density is consistent with an influx of gas. An oil influx would

                 have a greater density (0.3 to 0.4 psi/ft), and a saltwater influx would be
                 even more (around 0.47 psi/ft). Therefore, the difference in annulus and

                 drillpipe  pressures,  together  with  the  volume  of  the  influx,  allows  the

                 probable type of influx to be calculated. It is important in particular to

                 identify whether the influx is gas or not because this affects the well kill
                 operation. Gas is much harder to handle; as it moves up the annulus, its
                 pressure will drop. As the pressure drops, the volume will increase as

                 predicted by Boyle’s law. Boyle’s law states that for a fixed mass of gas
                 at a fixed temperature, pressure is inversely proportional to volume. If the

                 volume is halved, the pressure will double. If this volume expansion is not
                 allowed to happen, pressures on the well will increase and may exceed
                 rock strength somewhere.
                    Next, the pressure in the kicking formation can be calculated.
                 Calculations of hydrostatic pressure were covered in chapter 1. As the fluid


                 inside the drillstring should not be contaminated with influx, the drillpipe
                 pressure (P ) is used to calculate the bottomhole pressure, BHP, which
                           dp
                 equals formation pressure.


                       BHP = Hydrostatic pressure + P  =  (0.5 psi/ft  ×  8,000 ft)
                                                      dp
                                        + 500 psi = 4,500 psi

                    To kill the well and restore primary control, a heavier mud must be
                 circulated into the well. To give a hydrostatic pressure of 4,500 psi at
                 8,000 ft, the kill mud density gradient (ρ ) can be calculated. (The Greek
                                                       2
                 letter ρ [rho] is used to signify a density gradient; ρ  refers to the original
                                                                 1
                 mud density, and ρ  to the kill mud density.)  This calculation is shown in
                                  2
                 equation (11.2):

                                            4,500 psi
                                     ρ  = ———— =  0.563 psi/ft                  (11.2)
                                      2     8,000 ft

                    While preparations are made to kill the well, the mud engineer can
                 start to add barite to the mud in the active system to increase the density
                 gradient to 0.563 psi/ft. Meanwhile, some more calculations have to be
                 made before the kill can start.









        _Devereux_Book.indb   271                                                 1/16/12   2:12 PM
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