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0593_C02_fm  Page 26  Monday, May 6, 2002  1:46 PM





                       26                                                  Dynamics of Mechanical Systems



                                                                        C


                                                                           B



                                                                      A                    L
                                                                                 B
                       FIGURE 2.6.3                                     A
                       A vector sum projected onto a line L.   O

                       That is, the scalar may be placed anywhere in the product. The parentheses are unneces-
                       sary. The dot, however, must remain between the vectors.
                        Next, suppose n , n , and n  are mutually perpendicular unit vectors parallel to X-, Y-,
                                       x
                                          y
                                                 z
                       and Z-axes, and suppose V is a nonzero vector, as in Figure 2.6.4. Let θ , θ , and θ  be the
                                                                                               z
                                                                                        y
                                                                                      x
                       angles between V and the X-, Y-, and Z-axes. Then, the projections of V onto X, Y, and Z are:
                                        ⋅
                                                                          ⋅
                                                         ⋅
                                      Vn =    V cosθ      V n =  V cosθ      Vn =  V cosθ      (2.6.18)
                                           x        x      y         y      z         z
                       Then, from Eq. (2.6.11), if V , V , and V  are mutually perpendicular components of V
                                                   y
                                                x
                                                           z
                       parallel to X, Y, and Z, we can express V , V , and V  as:
                                                               y
                                                                      z
                                                           x
                                                         y (
                                         V = ( V n n )  V =    ⋅  y)   V = ( V n n )
                                                                              ⋅
                                                ⋅
                                          x       x  x       V n n       z      z  z           (2.6.19)
                                                                    y
                       Then, we also may express V as:
                                                                        )
                                       V = V + V +  V = ( Vn n )  + ( V n n +( Vn n )
                                                           ⋅
                                                                     ⋅
                                                                               ⋅
                                             x   y   z       x  x      y  y       z  z
                                                                                               (2.6.20)
                                                                      = V  n + V  n + V  n
                                                         x  x  y  y   z  z
                       where V , V , and V  are the scalar components of V along X, Y, and Z.
                                         z
                              x
                                 y
                        As a final example, suppose n , n , and n  are mutually perpendicular unit vectors, and
                                                   1
                                                      2
                                                             3
                       suppose A and B can be expressed as:
                                                    A =  A n + A n +  A n                      (2.6.21)
                                                         1 1   2  2   3  3
                                                       =
                                                     BB n +   B n +  B n                       (2.6.22)
                                                         1 1   2  2  3  3
                       Then, by using Eqs. (2.6.8), (2.6.16), and (2.6.17), we can express A · B as:
                                         AB (   A n  +  A n  +  n  B n  +  B n  + B )
                                           ⋅=
                                                                                 n
                                                                3
                                                              3
                                                 1  1  2  2  A ) ⋅( 1  1  2  2  3  3
                                                                            ⋅
                                                     ⋅
                                             =  AB nn   +  AB nn    +  AB nn
                                                                ⋅
                                                11  1  1   1 2  1  2   1 3  1  3
                                               +  AB n  ⋅n  +  AB n  ⋅n  +  AB n  ⋅n           (2.6.23)
                                                  21  2  1   3  2  3  2  2  3  2  3
                                                                     +
                                               +  AB n  ⋅n  +  AB n  ⋅n + AB n  ⋅n
                                                  31  3  1   3  2  3  2  3  3  3  3
                                             = A B  + AB  + AB
                                                1 1   2  2   3  3
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