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0593_C13_fm  Page 455  Monday, May 6, 2002  3:21 PM





                       Introduction to Vibrations                                                  455



















                       FIGURE 13.7.4                            FIGURE 13.7.5
                       Particle movement at lowest frequency ω 1 .  Particle movement at intermediate frequency ω 2 .














                       FIGURE 13.7.6
                       Particle movement at highest
                       frequency ω 3 .





                       13.8 Analysis and Discussion of Three-Particle Movement:
                             Modes of Vibration

                       In reviewing the foregoing analysis of the three-particle system we see a striking similarity
                       to the analysis for the eigenvalue problem of Sections 7.7, 7.8, and 7.9. Indeed, a comparison
                       of Eqs. (13.7.13), (13.7.14) and (13.7.15) with Eq. (7.7.10), shows that they are in essence
                       the same problem. This means that analyses similar to those of Sections 7.7, 7.8, and 7.9
                       (such as determination of eigenvalues, eigenvectors, orthogonality, etc.) could also be
                       conducted for the three-particle vibration problem. In our relatively brief introduction to
                       vibrations, however, it is not our intention to develop such detail. Instead, we plan to
                       simply introduce the concept of vibration modes (analogous to eigenvectors).
                        To this end, consider again the governing differential equations for the spring-supported
                       particles (see Eqs. (13.7.1), (13.7.2), and (13.7.3)):

                                                      mx ˙˙ +  2 kx − kx =  0                  (13.8.1)
                                                         1    1    2

                                                    mx ˙˙ − kx +  2 kx − kx =  0               (13.8.2)
                                                      2    1    2    3

                                                      mx ˙˙ − kx +  2 kx =  0                  (13.8.3)
                                                         3   2     3
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