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0593_C02_fm  Page 33  Monday, May 6, 2002  1:46 PM





                       Review of Vector Algebra                                                     33


                       Example 2.7.1: Vector Product Computation and Geometric Properties of
                       the Vector Product
                       Let vectors A and B be expressed in terms of mutually perpendicular dextral unit vectors
                       n , n , and n  as:
                                  3
                        1
                           2
                                                                    =
                                           A = 7 n − 2 n + 4 n     and    B n + 3 n − 8 n      (2.7.24)
                                                 1    2    3           1    2    3
                       Let C be the vector product A × B.

                          a. Find C.
                          b. Show that C is perpendicular to both A and B.
                          c. Show that B × A = –C.
                        Solution:


                             a. From Eq. (2.7.24), C is:

                                                  n  1  n 2  n 3
                                              C = 7   −2    4  = 4 n + 60 n + 23 n 3           (2.7.25)
                                                                        2
                                                                  1
                                                  1    3   −8
                          b. If C is perpendicular to A, with the angle θ between C and A being 90˚, C • A
                             is zero because cosθ is zero. Conversely, if C • A is zero, and neither C nor A is
                             zero, then cosθ is zero, making C perpendicular to A. From Eq. (2.6.21), C • A is:


                                                 ⋅
                                                        7
                                                                     2
                                                      4
                                                                 2
                                                                         4
                                                             60
                                               CA = ()( ) + ( ) − ( ) + ( )( ) = 0             (2.7.26)
                                                                      3
                             Similarly, C · B is
                                                 ⋅
                                                        1
                                                            60
                                                                3
                                                                        8
                                               CB = ()( ) + ( )( ) + ( ) − ( ) = 0             (2.7.27)
                                                                    2
                                                                     3
                                                      4
                          c. From Eq. (2.7.23), B × A is:
                                                   n   n     n
                                                    1    2    3
                                             ×
                                            BA = 1      3    − =−4 n − 60 n − 23 n             (2.7.28)
                                                              8
                                                                    1     2     3
                                                   7    −2   4
                             which is seen to be from Eq. (2.7.25).
                       2.8  Vector Multiplication: Triple Products
                       On many occasions it is necessary to consider the product of three vectors. Such products
                       are called “triple” products. Two triple products that will be helpful to use are the scalar
                       triple product and the vector triple product.
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