Page 236 - Electrical Safety of Low Voltage Systems
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Safety Against Static Electricity and Residual V oltages     219


                                     Needless to say that for static electricity purposes we must only
                                  earth metal objects isolated from ground, or whose resistance-to-
                                  ground is greater than 1 M . We have previously substantiated, in
                                  fact, that by connecting to the main grounding system metal objects
                                  other than these ones, we make them prone to transferred potentials
                                  generated in faulty equipment.


                             13.5 Residual Voltages
                                  Residual voltages are potentials caused by static charge accumulated
                                  in capacitors within equipment during its normal operation. Residual
                                  voltages may persist after the supply has been turned off, even for
                                  hours, and may expose maintenance personnel to the risk of electro-
                                  cution.
                                     During normal operations of electrical systems, voltages across
                                  capacitors are sinusoidal, and after disconnection of supply they re-
                                  main charged at the value V 0 the sinusoid had at the instant of the
                                  interruption.
                                     Upon direct contact with one, or both terminals, of the capacitor,
                                  the discharge process will initiate and its potential will decay with
                                  exponentiallaw.Suchpotentialwillcausethecirculationofanimpulse
                                  current through the person’s body of duration in the order of a few
                                  milliseconds. If we assume constant the person’s body resistance R B ,
                                  such current, as a function of time, can be expressed by using the
                                  Ohm’s law:

                                                        V 0   −  t        t
                                                   i(t) =  × e  R B C  = I peak e  −     (13.9)
                                                        R B
                                  where   indicates the time constant of the discharge process.
                                     The r.m.s. value of the discharge current can be calculated as:

                                                            I peak  V 0
                                                      I rms = √  =   √                (13.10)
                                                              6    R B 6

                                  We can assume that the above impulse current will have practically
                                  transferred almost the whole static energy accumulated in the capac-
                                  itor in a period of time equal to 3 . At this time, the current will be at
                                  5% of its initial value (Fig. 13.4).
                                     The energy E R released during the discharge and dissipated in
                                  the person’s body is the quantity that determines the probability of
                                  ventricular fibrillation.
                                     E R can be so expressed as:

                                                               3
                                                ∞
                                                   2    ∼        2    ∼    2
                                       E R = R B  i (t)dt = R B  i (t)dt = R B I rms 3   (13.11)
                                               0             0
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