Page 106 - Electromagnetics
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Substituting for ∇× B from (2.317) we then obtain

                                                           2
                                                          ∂ E        ∂
                                         ∇× (∇× E) + µ 0 
 0  2  =−µ 0  (J + J M + J P ),     (2.320)
                                                           ∂t       ∂t
                        which is the wave equation for E. Taking the curl of (2.317) and substituting from (2.316)
                        we obtain the wave equation

                                                            2
                                                           ∂ B
                                         ∇× (∇× B) + µ 0 
 0  2  = µ 0 ∇× (J + J M + J P )    (2.321)
                                                           ∂t
                        for B. Solution of the wave equations is often facilitated by writing the curl-curl operation
                        in terms of the vector Laplacian. Using (B.47), and substituting for the divergence from
                        (2.318) and (2.319), we can write the wave equations as

                                                  2
                                                 ∂ E   1               ∂
                                        2
                                      ∇ E − µ 0 
 0  2  =  ∇(ρ + ρ P ) + µ 0  (J + J M + J P ),  (2.322)
                                                 ∂t    
 0             ∂t
                                                  2
                                                 ∂ B
                                        2
                                      ∇ B − µ 0 
 0  2  =−µ 0 ∇× (J + J M + J P ).            (2.323)
                                                 ∂t
                        The simplicity of these equations relative to (2.312) and (2.313) is misleading. We have
                        not considered the constitutive equations relating the polarization P and magnetization
                        M to the fields, nor have we considered interactions leading to secondary sources.
                        2.10.3   Wave equation in a conducting medium
                          As an example of the type of wave equation that arises when secondary sources are
                        included, consider a homogeneous isotropic conducting medium described by permittivity
                        
, permeability µ, and conductivity σ. In a conducting medium we must separate the
                                                               i
                        source field into a causative impressed term J that is independent of the fields it sources,
                                            s
                        and a secondary term J that is an effect of the sourced fields. In an isotropic conducting
                                                                  s
                        medium the effect is described by Ohm’s law J = σE. Writing the total current as
                                 s
                            i
                        J = J + J , and assuming that J m = 0, we write the wave equation (2.314) as
                                                                        i
                                                             2
                                                            ∂ E       ∂(J + σE)
                                             ∇× (∇× E) + µ
     =−µ            .              (2.324)
                                                             ∂t 2        ∂t
                        Using (B.47) and substituting ∇· E = ρ/
, we can write the wave equation for E as
                                                               2
                                                      ∂E     ∂ E     ∂J i  1
                                              2
                                             ∇ E − µσ    − µ
    = µ     + ∇ρ.                (2.325)
                                                      ∂t      ∂t 2    ∂t
                                        i
                        Substituting J = J + σE into (2.315) and using (B.47), we obtain
                                                              2
                                                             ∂ H
                                                     2                  i
                                          ∇(∇· H) −∇ H + µ
      =∇ × J + σ∇× E.
                                                             ∂t  2
                        Since ∇× E =−∂B/∂t and ∇· H =∇ · B/µ = 0,wehave
                                                                 2
                                                        ∂H      ∂ H         i
                                                2
                                              ∇ H − µσ     − µ
     =−∇ × J .                 (2.326)
                                                        ∂t      ∂t 2
                        This is the wave equation for H.



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