Page 517 - Electromagnetics
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Helmholtztheorem




                                                     ∇ · A(r )        A(r ) · ˆ n


                                       A(r) =−∇               dV −             dS  +

                                                   V 4π|r − r |      S 4π|r − r |

                                                      ∇ × A(r )        A(r ) × ˆ n




                                           +∇ ×                dV +             dS             (B.33)

                                                    V 4π|r − r |      S 4π|r − r |
                        Miscellaneous identities

                                                            dS = 0                             (B.34)
                                                           S

                                                      ˆ n × (∇a) dS =  adl                     (B.35)
                                                     S

                                            (∇a ×∇b) · dS =   a∇b · dl =−   b∇a · dl           (B.36)
                                           S

                                                      dl A =  ˆ n × (∇A) dS                    (B.37)
                                                             S
                        Derivative identities


                                    ∇ (a + b) =∇a +∇b                                          (B.38)
                                    ∇· (A + B) =∇ · A +∇ · B                                   (B.39)
                                    ∇× (A + B) =∇ × A +∇ × B                                   (B.40)
                                    ∇(ab) = a∇b + b∇a                                          (B.41)
                                    ∇· (aB) = a∇· B + B ·∇a                                    (B.42)
                                    ∇× (aB) = a∇× B − B ×∇a                                    (B.43)
                                    ∇· (A × B) = B ·∇ × A − A ·∇ × B                           (B.44)
                                    ∇× (A × B) = A(∇· B) − B(∇· A) + (B ·∇)A − (A ·∇)B         (B.45)
                                    ∇(A · B) = A × (∇× B) + B × (∇× A) + (A ·∇)B + (B ·∇)A     (B.46)
                                                             2
                                    ∇× (∇× A) =∇(∇· A) −∇ A                                    (B.47)
                                               2
                                    ∇· (∇a) =∇ a                                               (B.48)
                                    ∇· (∇× A) = 0                                              (B.49)
                                    ∇× (∇a) = 0                                                (B.50)
                                    ∇× (a∇b) =∇a ×∇b                                           (B.51)
                                               2
                                      2
                                                                   2
                                    ∇ (ab) = a∇ b + 2(∇a) · (∇b) + b∇ a                        (B.52)
                                                       2
                                                2
                                      2
                                    ∇ (aB) = a∇ B + B∇ a + 2(∇a ·∇)B                           (B.53)
                                      2
                                    ∇ ¯ a =∇(∇· ¯ a) −∇ × (∇× ¯ a)                             (B.54)
                                    ∇· (AB) = (∇· A)B + A · (∇B) = (∇· A)B + (A ·∇)B           (B.55)
                                    ∇× (AB) = (∇× A)B − A × (∇B)                               (B.56)
                                    ∇· (∇× ¯ a) = 0                                            (B.57)
                        © 2001 by CRC Press LLC
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