Page 188 -
P. 188

Homework Problem

                             Pb. 6.55 Plot the magnitude and the phase of theTransfer Function given in
                             Eq. (6.87) as a function of ω, for LC = 1, RC = 3.




                             6.8.2  The Infinite LC Ladder
                             The LC ladder consists of an infinite repetition of the basic elements shown in
                             Figure 6.2.

                                       V n                  V n+1
                                                  Z 1                 Z 1
                                          I n                   I n+1
                                       Z 2                  Z 2               Z 2
                                                  (I n –  I n+1 )


                              FIGURE 6.2
                              The circuit of an infinite LC ladder.

                             Using the definition of impedances, the phasors of the n and (n + 1) voltages
                             and currents are related through:


                                                        ˜
                                                        V −  V  =  Z I ˜                   (6.88)
                                                            ˜
                                                         n   n+1   1  n
                                                       ˜
                                                             ˜
                                                      V   = (I −  I ˜  )Z                  (6.89)
                                                        n+1   n  n+1  2
                                                                                ˜
                             From Eq. (6.88), we deduce the following expressions for  I and  ˜ I  :
                                                                                 n     n+1
                                                            V − V
                                                             ˜
                                                                 ˜
                                                         I =  n   n+1                      (6.90)
                                                         ˜
                                                         n
                                                               Z
                                                                1
                                                             ˜
                                                            V   −  V ˜
                                                       ˜ I  =  n+1  n+2                    (6.91)
                                                        n+1
                                                                Z
                                                                 1
                             Substituting these values for the currents in Eq. (6.89), we deduce a second-
                             order difference equation for the voltage phasor:
                                                          Z  
                                                                     ˜
                                                   ˜
                                                  V   −   1  + 2  V ˜  + V = 0           (6.92)
                                                    n+2          n+1  n
                                                          Z 2  
                             © 2001 by CRC Press LLC
   183   184   185   186   187   188   189   190   191   192   193