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P. 277

Physically, the above result can be interpreted as the precession of the elec-
                             tron around the direction of the magnetic flux density. To understand this
                             statement, let us find the eigenvectors of the σσ σσ  and σσ σσ  matrices. These are
                                                                             y
                                                                       x
                             given by:

                                                α =  1    1  and  β =  1   1         (8.65a)
                                                                         
                                                         
                                                 x                 x
                                                      2    1         2   −  1
                                                α =  1    1  and  β =  1   1         (8.65b)
                                                                         
                                                        
                                                 y       j      y        j − 
                                                      2                2  
                             The eigenvalues of σσ σσ  and σσ σσ  corresponding to the eigenvectors αα αα are equal to
                                               x
                                                     y
                             1, while those corresponding to the eigenvectors ββ ββ are equal to –1.
                              Now, assume that the electron was initially in the state αα αα :
                                                                                x
                                                        a()0   1  
                                                                 1
                                                           =     =α x                  (8.66)
                                                       b()0   2 1  
                             By substitution in Eq. (8.64), we can compute the electron spin state at differ-
                             ent times. Thus, for the time indicated, the electron spin state is given by the
                             second column in the list below:

                                                        π
                                                    t =    ⇒ ψ  =  e  j − π 4/  α          (8.67)
                                                       2Ω               y


                                                        π
                                                     t =  ⇒ ψ   =  e  j − π/2 β            (8.68)
                                                        Ω              x

                                                       3π
                                                    t =   ⇒ ψ   =  e  j − 3π/ 4 β          (8.69)
                                                       2Ω               y

                                                        2π
                                                     t =   ⇒ ψ   =  e  j − π α             (8.70)
                                                         Ω             x

                              In examining the above results, we note that, up to an overall phase, the
                             electron spin state returns to its original state following a cycle. During this
                             cycle, the electron “pointed” successively in the positive x-axis, the positive
                             y-axis, the negative x-axis, and the negative y-axis before returning again to
                             the positive x-axis, thus mimicking the hand of a clock moving in the coun-
                             terclockwise direction. It is this “motion” that is referred to as the electron
                             spin precession around the direction of the magnetic flux density.


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