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an initial velocity v  in the x-direction and v  in the y-direction satisfies the
                                             0, x
                                                                    0, y
                             following parametric equations:
                                                 x =  v t and  y = −  1 gt +  v t
                                                                     2
                                                     0, x                0, y
                                                                  2
                             where t is time and the origin of the axis was chosen to correspond to the
                             position of the particle at t = 0 and g = 9.8 ms –2
                                a. By eliminating the time t, show that the projectile trajectory y(x) is
                                   a parabola.
                                b. Noting that the components of the initial velocity can be written
                                   as function of the projectile initial speed and its angle of inclination:

                                              v  = v  sin(φ)  and v  = v  cos(φ)
                                                                        0
                                                                   0, x
                                               0, y
                                                    0
                                   show that, for a given initial speed, the maximum range for the
                                   projectile is achieved when the inclination angle of the initial veloc-
                                   ity is 45°.
                                c. Plot the range for a fixed inclination angle as a function of the initial
                                   speed.







                             3.4  Examples with Polynomial Functions

                             As pointed out in the Supplement, a polynomial function is an expression of
                             the form:

                                                px() =  a x +  a  x n−1  +…+ a x +  a       (3.9)
                                                        n
                                                      n     n−1         1   0
                                              th
                             where a ≠ 0 for an n -degree polynomial. In MATLAB, we can represent the
                                   n
                             polynomial function as an array:
                                                        p = [ a a  … a ]                   (3.10)
                                                            nn−1   0
                             Example 3.1
                             You are given the array of coefficients of the polynomial. Write a function M-
                             file for this polynomial using array operations. Let p = [132103]:

                             Solution:

                                function y=polfct(x)
                                p=[1 3 2 1 0 3];


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