Page 93 - Bruno Linder Elementary Physical Chemistry
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August 18, 2010 11:36      9in x 6in     b985-ch07     Elementary Physical Chemistry





                               78                   Elementary Physical Chemistry

                                  It is assumed that a molecule A collides with another molecule A
                               to produce an energetically excited molecule A . The following reactions
                                                                        ∗
                               (assumed to be elementary) occur. In all these reactions, the rate constants
                               k 1 and k 2 are in the forward direction, and k is in the reverse direction.

                                                                      1
                                                                   ∗
                                                      1) A + A → A +A
                                                            ∗
                                                         d[A ]/dt = k 1 [A] 2             (7.54)
                                    ∗
                               The A molecule may lose its energy by colliding with another molecule A.
                                                     ∗
                                                 2) A +A → A+A
                                                    −d[A ]/dt = k [A ][A] fast            (7.55)
                                                         ∗

                                                                    ∗
                                                                 1
                               or A may shake itself apart, by undergoing a unimolecular reaction
                                  ∗
                                                       ∗
                                                  3) A → P
                                                          ∗
                                                                     ∗
                                                     −d[A ]/dt = k 2[A ] slow             (7.56)
                               Assuming that A is the intermediate, and thus
                                              ∗
                                                 ∗
                                              d[A ]/dt =0
                                                             2

                                                                    ∗
                                                                              ∗
                                                      = k 1 [A] − k [A ][A] − k 2 [A ]   (7.57a)
                                                                 1
                               which gives
                                                     ∗       2
                                                   [A ]= k 1 [A] /{k 2 + k [A]}          (7.57b)
                                                                      1
                               Finally, if (not always true) reaction (3) is very much slower than (2), and
                               thus k   k 2 ,we obtain

                                    1
                                                      ∗
                                                    [A ]= k 1 /k [A]= k[A}               (7.58a)
                                                              1
                               and therefore,

                                                  −d[A ]/dt =d[P]/dt = k[A]              (7.58b)
                                                       ∗

                               which is first order.
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