Page 94 - Bruno Linder Elementary Physical Chemistry
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August 18, 2010 11:36      9in x 6in     b985-ch07     Elementary Physical Chemistry





                                                    Chemical Kinetics                      79

                            7.15. Chain Reactions

                            Many liquid and gaseous reactions are chain reactions, meaning that
                            an intermediate produced in one step generates an intermediate in a
                            subsequent step; the latter generates another intermediate, etc.
                               It is customary to characterize the various reactions by names, such as
                            initiation step, propagation step, termination step, etc.
                               As an example, consider the reaction
                                                H 2 (g) + Br 2 (g) → 2HBr(g)           (7.59)

                            Theratelaw is found to be
                                        d[HBr]/dt = k[H 2 ][Br 2 ] 3/2 /([Br 2 ]+ k [HBr])  (7.60)

                            The proposed mechanism involves chain reactions and free radicals. A
                            radical is denoted by a dot after the atomic symbol. The final results must
                            not contain intermediate free radicals. Again, all reaction constants are in
                            the forward direction.

                            1) Initiation

                                                        Br 2 → 2Br •
                                                   1/2d[Br •]/dt = k a [Br 2 ]         (7.61)
                            2) Propagation

                                                    Br • +H 2 → HBr + H •
                                             −d[Br •]/dt =d[H ]/dt = k b[Br •][H 2]    (7.62)
                                                             •

                                                   H •  +Br 2 → HBr + Br •
                                             −d[H ]/dt =d[Br •]/dt = k [H ][Br 2 ]     (7.63)

                                                  •
                                                                        •
                                                                     b
                            3) Retardation
                                                     •
                                                    H +HBr → H 2 +Br •
                                             −d[H ]/dt =d[Br •]/dt = k c [H ][HBr]     (7.64)
                                                                        •
                                                  •
                            4) Termination
                                                 Br • +Br • +M → Br 2 +M
                                                     1                 2
                                                   − d[Br •]/dt = k d[Br •]            (7.65)
                                                     2
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