Page 122 - Elements of Chemical Reaction Engineering 3rd Edition
P. 122

Rate Laws and Stoichiometry   Chap. 3






                           In gas-phase systems that we shall be studying, the temperatures and pressures
                           are such that the compressibility factor will not change significantly during the
                           course of the reaction; hence  Zo = 2. For a batch system the volume of gas at
                           any time t is

            Volume of gas for
            a variable volume
               batch reaction

                          Equation (3-38) applies only to a variable-volume batch reactor. If  the reactor
                          is  a rigid  steel container of  constant volume, then  of  course  V = Vo. For  a
                          constant-volume container, V = V,,  and Equation (3-38) can be used to calcu-
                          late the pressure inside the reactor as a function of temperature and conversion.
                               An  expression  similar  to  Equation  (3-38)  for  a  variable-volume batch
                          reactor exists for a variable-volume flow system. To derive the concentrations
                          of  the species in terms of  conversion for a variable-volume flow  system, we
                           shall use the relationships for the total concentration. The total concentration'at
                          any point in the reactor is

                                                         F~
                                                     C  --=-    p
                                                      T-  u    ZRT
                          At the entrance to the reactor,




                               Taking the ratio of Equatlon (3-40) to Equation (3-39) and assuming neg-
                          ligible changes in the compressibility factor, we have upon rearrangement






                          From Table 3-3, the total molar flow rate is

                                                    FT = FTo + FAo 6X
                           Substituting for FT  in Equation (3-41) gives
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