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                                         3.3 Further Properties of Characteristic Functions   87

                        Example 3.14 (Uniform distribution on the unit interval). Consider the uniform distri-
                        bution on the unit interval; the characteristic function of this distribution is given by
                                   1
                                               exp(it) − 1  sin(t)   cos(t) − 1
                          ϕ(t) =   exp(itx) dx =         =      − i            , −∞ < t < ∞.
                                 0                 it        t           t
                        Hence,
                                                2
                                            sin(t) + (cos(t) − 1) 2
                                        2                            −2
                                    |ϕ(t)| =                   = O(|t| )as |t|→∞
                                                    t 2
                        so that the density of this distribution is differentiable, at most, one time. Here p(x) = 1if
                        0 < x < 1 and p(x) = 0 otherwise so that p is not differentiable.

                        Example 3.15 (Binomial distribution). Consider a binomial distribution with parameters
                        n and θ. The characteristic function of this distribution is given by

                                                 ϕ(t) = [1 − θ + θ exp(it)] n
                        so that
                                                                             n
                                                                           2
                                                       2
                                         |ϕ(t)|= [(1 − θ) + 2θ(1 − θ) cos(t) + θ ] 2 .
                        It is easy to see that
                                                          n
                                       lim inf |ϕ(t)|=|2θ − 1|  and  lim sup |ϕ(t)|= 1
                                        |t|→∞
                                                                   |t|→∞
                        so that ϕ(t) does not have a limit as |t|→ 0; see Figure 3.2 for a graphical illustration of
                        this fact. It follows that the binomial distribution is not absolutely continuous, which, of
                        course, is obvious from its definition.

                        Symmetric distributions
                        The distribution of X is said to be symmetric about a point x 0 if X − x 0 and −(X − x 0 )
                        have the same distribution. Note that this implies that

                                        F(x 0 + x) = 1 − F((x 0 − x)−), −∞ < x < ∞,
                        where F denotes the distribution function of X.
                          The following theorem shows that the imaginary part of the characteristic function of a
                        distribution symmetric about 0 is 0; the proof is left as an exercise.

                        Theorem 3.10. Let X denote a real-valued random variable with characteristic fun-
                        ction ϕ. The distribution of X is symmetric about 0 if and only if ϕ(t) is real for all
                        −∞ < t < ∞.

                        Example 3.16 (Symmetrization of a distribution). Let X denote a real-valued random
                        variable with characteristic function ϕ. Let X 1 , X 2 denote independent random variables,
                        such that X 1 and X 2 each have the same distribution as X, and let Y = X 1 − X 2 . Then Y
                        has characteristic function
                                         ϕ Y (t) = E[exp(it X 1 )exp(−it X 2 )] = ϕ(t)ϕ(−t)
                                                                               .
                                                    2
                                             =|ϕ(t)| , −∞ < t < ∞
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