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Chap. 6   Questions and Problems                               333


                                                     (2)  PBA+OA     k2  >  E+BA
                                                     (3)  BfPBA     k3  >  2BA

                                       Additional information:
                                       Concentration of pure B  = 9.8 km01/m3
                                       Concentration of pure. OA  = 3.15 km0Vm3
                                       Catalyst concentration = 4 x 10-5 km0l/m3
                                                           -
                                  ,+-[c;~~]O.S[B]1.7   kl  = 1'745 k;r min-1  at 47°C with E,  = 18,500 caI/mcil and
                              rI = -
                                  (l f'K1[0A1)0'7
                                                 K,  = 64.03 m3/hol
                                                          b;Jl

                              r2 = kz[PBA]0.5[OA]0~6 k, = 0.178  - anin-'  at 47°C with E,  = 9177 cal/mol

                                                 k, = 0.08 min-'  at 47°C with E, = 17,132 caYmol and
                                    k3 [PB A]
                              r, = -             K, = 8.064 m3/kmoi
                                  (1 + ,K3[0A])1.0
                                        How should the reaction be carried out (e.g. type of reactor(s>, volume, tem-
                                        perature, feed rate) to produce 100 kmol of  oleic acid expoxide (E) per day?
                                        There will be a prize for the solution that meets this criteria and minimizes the
                                        undesirable products. If equipment costs are available they should be included.


                                 P6-26,: A new catalytic pathway for an important intermediate in  the productlion  of
                                        the  nonsteroidal  anti-inflammatory  drug  ibuprofen  (e.g.,  Advil)  has  been
                                        developed [Chern. Eng. Sci., SI, 10, 1663 (1996)l. The pathway involvles the
                                        hydrogenation of p-isobutyl acetophenone (B) in a solution of methanol con-
                                        taining a HY zeolite catalyst and  saturated with hydrogen. The intermediate
                                        products are p-isobutylphenyl ithanol (C), p-isobutylphenylethylmethyl ether
                                        (E) and p-isobutylethyl benzene (F). The reaction scheme is shown below.







                                                       (4)   E+A--+F+M.

                                        The following rate laws apply to the above equation.
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