Page 516 - Elements of Chemical Reaction Engineering Ebook

486 Steady-State Nonisothermal Reactor Design Chap. 8
For the SO, oxidation, SO, + 10, + SO, ,

ACX = as0 -~~x~,-Lx~~, -(0.5)(5.731)-7.208 = -1.563
8.511
=
Similarly,

Ap = 0.00262 and Ay = -0.738 X
Substituting into Equation (E8-10.13) with TR = 1260"R, we have

AHRx(T) = -42,471 -(1.563)(T- 1260)+(1.36X 10-3)(T2- 1260,)
- (2.459 X 10-7)(T3 - 1260,) (E8-10.14)

Oi Cpi = 57.23 + 0.0142- - 1.94 X 10-6TZ (E8-IO. 15)
Heat-transfer coeficient term:
UnD- 4U - 4(10 Btu/h*ftz-oR)
----
pbA, pbD (33.8 lb/ft3)[(2.78/12) ft]
= 5.11 Btu/h.lbcat.R

Energy balance

that is,

E= f,(T,P,X) (E8-10.17)
dW
7. Pressure drop: After rearranging Equation (4-23), the pressure drop is given by

Momentum balance

where
G=- X Fjo Mi (Mi molecular weight of i)
=
A,
= 1307.6 lb/ft2.h
A, = cross-sectional area nD2/4

Recalling that W = pbA,z, we obtain

8. Evaluating the pressure-drop parameters: