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152    7. Galois Cohomology and Isomorphism Classification of Elliptic Curves

                                                  δ
                                        0
                 0
                             0
                                                                 1
                                                      1
                        i ∗
                                                             i ∗
           1 → H (G, A) → H (G, E) → H (G, E/A) → H (G, A) → H (G, E).
        Further, if A is a normal subgroupof E, then
                                      1
                                                  1
                           1
                         H (G, A) → H (G, E) → H (G, E/A)
        is an exact sequence of pointed sets so that the entire six-term sequence is exact.
                                                               G
                                                                      G
        Proof. We have already shown that the image equals the kernel in A and E ,see
                                     0
                                                                     1
                                G
        (2.6). For exactness at (E/A) = H (G, E/A) observe that δ(X) = 1in H (G, A)
        is equivalent to the coset X having the form xA with s(x) = x for all s ∈ G by (3.8).
        In other words, it is equivalent to the principal homogeneous G-set X being in the
                  0
                             0
        image of H (G, E) → H (G, E/A).
                               1
                                                        1
           To show exactness at H (G, A), we consider [a s ] ∈ H (G, A) whose image in
          1
        H (G, E) is trivial. This means for A ⊂ E that there exists e ∈ E with a s = e −1 s
                                                                        ( e)
                        s                                       0
        for all s ∈ G. Then e = ea s andwehave[a s ] = δ(eA), where eA ∈ H (G, E/A) =
                                                        1
              G
                               1
        (E/A) . Clearly δ(eA) in H (G, A) has trivial image in H (G, E).
                                                            1
           When A is a normal subgroup of E, we prove exactness at H (G, E). Let [a s ] ∈
          1
                                     1
        H (G, E) have trivial image in H (G, E/A), that is, suppose there exists e ∈ E
        with a s = e −1 s                              s         s
                    ( e)b s with b s ∈ A for all s ∈ G. Since ( e)A = A( e),wehave
        c s ∈ A with
                                            s
                               ( e)b s = e
                        a s = e −1 s   −1 c s e  for all s ∈ G.
                                         1
        Then c s ∈ Z −1 (G, A) defining [c s ] ∈ H (G, A) which maps to [a s ] under i ∗ . This
        proves the theorem.
                                                               i
        (4.4) Remark. When A is commutative, it is possible to define H (G, A) for all
        i ≥ 0 algebraically. The six-term sequence of (4.3) becomes seven term for A abelian
        and normal in E. It has the form
                      0       i ∗  0         0          δ  1       i ∗
                1 → H (G, A) → H (G, E) → H (G, E/A) → H (G, A) →
                                               δ
                                     1
                                                   2
                         1
                        H (G, E) → H (G, E/A) → H (G, A).
        If both A and E are commutative we have an exact triangle or long exact sequence
               i
        for all H of A, E,and E/A of the form
                                         i ∗
                                              ∗
                                 ∗
                               H (G, A) −→ H (G, E)
                                     H (G, E/A)
                                      ∗
        where δ has degree +1.
        (4.5) Remark. Let f : G → G be a group homomorphism. If E is a G-group

                  s                                 s    f (s )


        with action x, then E is also a G -group with action x =  x and f induces a
                                                0
                         0
                                                               ∗
        natural morphism H (G, E) = E G  → E G     = H (G , E) denoted f and a natural

                              1
                   1
                                                  ∗
        morphism H (G, E) → H (G , E) also denoted f ([a s ]) = [a f (s ) ].
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