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156    7. Galois Cohomology and Isomorphism Classification of Elliptic Curves

                  s
                                   ( u) and b s = v
                                                  ( v), then the coboundary rela-
        a s = h −1 b s ( h), where a s = u −1 s  −1 s
                            s s s
                                        s


        tion leads to vhu −1  = v h (u −1 ) = (vhu −1 ) and vhu −1  : E → E is an iso-
        morphism over k between the two elliptic curves compared with E by u : E → E

        and v : E → E both isomorphisms over k.
                           1
                                                                   t
           For t = [a s ] ∈ H (Gal(k/k), Aut (E)) we define a twisted curve E by the
                                        k
                      t                                    s  s     s
        requirement that E(k) is the set of all (x, y) in E(k) satisfying ( x, y) = (x, y) =
                                           t
        a s (x, y). The difficulty is in showing that E(k) really is the set of k-points on an
        elliptic curve over k. We work out in detail that case where the cocycle has values
        in the subgroup {+1, −1} contained in Aut (E). Note it is equal to Aut (E) for
                                            k                       k
                    3
         j(E)  = 0, 12 . In this case t is a homomorphism t :Gal(k/k) → Z/2Z. Such
        homomorphisms are in one-to-one correspondence with quadratic extensions k t =
          √                                               √          √
        k( a) of k with nontrivial automorphism s satisfying s(x +  ay) = x −  ay.If
                     2
                                                             t
        E is given by y = f (x), a cubic polynomial f (x) over k, then E is givenbythe
                  2
                                                   t
        equation ay = f (x), and the isomorphism u : E → E is given by

                                              y
                                 u(x, y) = x, √   .
                                               a
        In terms of the general construction the relation
                 √         √                             √         √
                                            s
          − x +    ax , y +  ay  = a s (x, y) = (x, y) = x −  ax , y −  ay
        becomes in this case x      = 0and y = 0since −(x, y) = (x, −y). Finally,

            √         t


        (x ,  ay ) is on E(k) if and only if (x , ay ) is on E(k). The other cases, including


        characteristic 2, are left to be checked by the reader.

        (6.2) Summary. If E and E are two elliptic curves over k with j(E) = j(E )  =
            3



        0, 12 , then there is a quadratic extension k of k with E and E isomorphic over k .
        (6.3) Remark. In 3(6.3) we found that there are five elliptic curves over F 2 up to
        isomorphism of which two have j = 1 and three have j = 0. The two curves with
         j = 1 are isomorphic over a quadratic extension and Aut(E) is the two element
        group. These are the curves E 1 and E 2 , see 3(6, Ex. 1). We leave it to the reader to
        explain in terms of Galois cohomology the results in Exercises 1–5 of 3, §6 concern-
        ing over which field the pairs of curves over F 2 are isomorphic.
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