Page 50 -
P. 50

§1. Chord-Tangent Computational Methods on a Normal Cubic Curve  27

        0 = 2(−1, −1) = 2 · 3P = 6P since the tangent at (−1, −1) is vertical, and we
        deduce that P is a point of order 6. In particular
                            4P =−2P =−(0, 0) = (0, −1)

        and

                             5P =−P =−(1, 1) = (1, −1).

        Thus P m = mP,and O together with the five points P,2P,3P,4P, and 5P shown
        on the cubic E form a cyclic subgroup of order 6 in E(Q) in (1.3).

           If we study the question of when the product of three consecutive numbers y(y +
                                                              3
        1) is the product of three consecutive numbers (x − 1)x(x + 1) = x − x, we are led
        to the following example of an elliptic curve.
                                                                     2
        (1.6) Example. The elliptic curve E defined by the normal cubic equation y + y =
         3
        x − x has six obvious points on it (0, 0), (1, 0), (−1, 0), (0, −1), (1, −1),and
        (−1, −1).If P = (0, 0), then these points are all in the subgroup generated by P as
        with P = (1, 1) in (1.5), but in this case P generates an infinite cyclic group.


































           In general odd multiples of P are on the closed component of the curve which
        contains P = (0, 0) and the even multiples of P are on the open component which
        is closed up to a circle by adding O at infinity. We have the following values for a
   45   46   47   48   49   50   51   52   53   54   55