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               356                                                                              Electron Transfer Reactions


                                                 +
                        6MoO 2−  + 3(MoOH) 4+  + 14H →
                             4           2
                          3Mo 2 O 2+  + 2Mo 3 O 4+  + 10H 2 O
                                4         4
               with Mo(VI) atoms equally distributed in the prod-
               ucts. Evidently, (MoOH) 4+  on giving up electrons forms
                                   2
               oligomers. The first that is able to break up into only sta-
               ble products has 12 molybdenum atoms with an average
               oxidation state of 4.5.














                                                                 FIGURE 3 Oxidation state–potential diagrams for vanadium and
                                                                 chromium [1.0M H (aq)].
                                                                               +

                                                                 tance of kinetic control over the course of multistep pro-
                                                                 cesses. One-electron reducing agents produce NO, which
                                                                 escapes as a gas from an open system, before nitrogen is
               VII. PATHWAYS AMONG                               reduced to oxidation number zero. Two-electron reduc-
                                                                                                             +
                                                                                                     +
                   OXIDATION STATES                              ing agents (in excess) produce N 2 O, NH 3 OH , and NH ,
                                                                                                             4
                                                                 bypassing all states that require an odd number of elec-
                                                                                         −
               Oxidation state–potential diagrams for nonmetallic and  trons to be transferred to NO . HNO, which is isoelec-
                                                                                         3
               transition metal elements provide an interesting frame-  tronic with O 2 , is apparently an active intermediate in all
               work for analyzing the highly varied results obtained for  two-electron reductions of nitric acid. Most product pat-
               redox reactions involving as many as nine oxidation states.  terns can be rationalized by postulating traps for HNO as
               So many different products and stoichiometries are ob-  follows:
               tained from the reduction of nitric acid that early work
               seeking patterns of reaction was abandoned after many   HNO + HNO → HONNOH → N 2 O + H 2 O
               years of frustrating effort.
                                                                       (dimerization, no electron transfer).
                 Figures 3 and 4 show diagrams for the transition metals
               vanadium and chromium and for the nonmetal nitrogen,  Reducing agents:
               all in 1.0M aqueous acid solution. The slopes of lines                               2−
                                                                                                   ¨
                                                                                                ¨
                                                                                −
               joining redox couples represent the potentials for the half-  HNO+ :SnCl → Sn(IV) + H N O:
                                                                                3
                                                                                                ¨
                                                                                                   ¨
               reactionsinquestion,apositivesloperepresentingareduc-           2−
                                                                              ¨
                                                                          ¨
                                                                                      +
                                                                       H N O:    + 3H → H 3 NOH  +
               tion potential and a negative slope an oxidation potential.  ¨  ¨
               An intermediate state above tie lines joining higher and       −
                                                                       (direct 2e transfer)
               lower states will be unstable to disproportionation [e.g.,
                                                                                              ¨
               Cr(V) and NO 2 ] while species below such tie lines are sta-  HNO + Mo(IV) → [Mo N O H]‡ →
                                                                                              ¨
               ble [e.g., Cr(III) and N 2 ]. The diagrams are a convenient             2−
                                                                                    ¨
                                                                                ¨
                                                                                                    −
               way to postulate the feasibility of various possible one-  Mo(VI) + :N O  H   (direct 2e transfer)
                                                                                ¨   ¨
               and two-electron pathways in multistep redox processes
               involving a particular element.                   The last case makes possible transfer of two unpaired t 2g
                                                                 electrons from Mo(IV) by forming a triple bond in the
                                                                                                     −
                                                                 activated state using the π orbitals on NO , which are
                                                                                       ∗
               A. Reduction of Nitric Acid
                                                                 isolobal with two t 2g orbitals on Mo(IV). [Under sim-
               It is interesting to note that N 2 is seldom observed dur-                             −
                                                                 ilar circumstances Mo(IV) reduces two ClO to ·ClO 2
                                                                                                      3
               ing reductions of nitric acid, which shows the impor-  by separate one-electron transfers from the orthogonal
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