Page 152 - Engineering Electromagnetics, 8th Edition
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134                ENGINEERING ELECTROMAGNETICS

                                     the tangential components by using

                                                                   E · dL = 0

                                     around the small closed path on the left, obtaining
                                                            E tan 1  w − E tan 2  w = 0

                                        The small contribution to the line integral by the normal component of E along
                                     the sections of length  h becomes negligible as  h decreases and the closed path
                                     crowds the surface. Immediately, then,


                                                                                                     (32)
                                                                 E tan 1 = E tan 2
                                     Evidently, Kirchhoff’s voltage law is still applicable to this case. Certainly we have
                                     shown that the potential difference between any two points on the boundary that are
                                     separated by a distance  w is the same immediately above or below the boundary.
                                        If the tangential electric field intensity is continuous across the boundary, then
                                     tangential D is discontinuous, for

                                                          D tan 1              D tan 2
                                                               = E tan 1 = E tan 2 =
                                                             1                    2
                                     or
                                                                  D tan 1    1
                                                                       =                             (33)
                                                                  D tan 2    2
                                        The boundary conditions on the normal components are found by applying
                                     Gauss’s law to the small “pillbox” shown at the right in Figure 5.10. The sides are
                                     again very short, and the flux leaving the top and bottom surfaces is the difference

                                                        D N1  S − D N2  S =  Q = ρ S  S
                                     from which

                                                                                                     (34)
                                                               D N1 − D N2 = ρ S
                                        What is this surface charge density? It cannot be a bound surface charge density,
                                     because we are taking the polarization of the dielectric into effect by using a dielectric
                                     constant different from unity; that is, instead of considering bound charges in free
                                     space, we are using an increased permittivity. Also, it is extremely unlikely that any
                                     free charge is on the interface, for no free charge is available in the perfect dielectrics
                                     we are considering. This charge must then have been placed there deliberately, thus
                                     unbalancing the total charge in and on this dielectric body. Except for this special
                                     case, then, we may assume ρ S is zero on the interface and

                                                                  D N1 = D N2                        (35)
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