Page 277 - Engineering Electromagnetics, 8th Edition
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CHAPTER 8   Magnetic Forces, Materials, and Inductance    259


























                                  Figure 8.12 A hysteresis loop for silicon steel. The
                                  coercive force H c and remnant flux density B r are
                                  indicated.

                     hysteresis loops are obtained, and the locus of the tips is about the same as the virgin
                     magnetization curve of Figure 8.11.


                                                                                            EXAMPLE 8.7
                     Let us use the magnetization curve for silicon steel to solve a magnetic circuit problem
                     that is slightly different from our previous example. We use a steel core in the toroid,
                     except for an air gap of 2 mm. Magnetic circuits with air gaps occur because gaps
                     are deliberately introduced in some devices, such as inductors, which must carry
                     large direct currents, because they are unavoidable in other devices such as rotating
                     machines, or because of unavoidable problems in assembly. There are still 500 turns
                     about the toroid, and we ask what current is required to establish a flux density of 1 T
                     everywhere in the core.
                     Solution. Thismagneticcircuitisanalogoustoanelectriccircuitcontainingavoltage
                     sourceandtworesistors,oneofwhichisnonlinear.Becausewearegiventhe“current,”
                     it is easy to find the “voltage” across each series element, and hence the total “emf.”
                     In the air gap,

                                     d air     2 × 10 −3              6
                                 air =   =                  = 2.65 × 10 A·t/Wb
                                     µS    4π10 −7  × 6 × 10 −4
                     Knowing the total flux,
                                                       −4
                                        = BS = 1(6 × 10 ) = 6 × 10 −4  Wb
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