Page 400 - Engineering Electromagnetics, 8th Edition
P. 400

382                ENGINEERING ELECTROMAGNETICS


                                                                      J     ′E




                                                                    ′
                                                                               J       ′  E



                                                    J   E




                                                   Figure 11.2 The time-phase relationship
                                                   between J ds , J σs , J s , and E s . The tangent of θ
                                                   is equal to σ/ω  , and 90 − θ is the common
                                                                      ◦

                                                   power-factor angle, or the angle by which J s
                                                   leads E s .
                                     Considering a conductive material, for which   = σ/ω, (43) becomes


                                                                               σ

                                                            jk = jω µ      1 − j                     (59)
                                                                              ω
                                     We may expand the second radical using the binomial theorem
                                                               n(n − 1)    n(n − 1)(n − 2)
                                                    n                   2                3
                                              (1 + x) = 1 + nx +       x +              x +· · ·
                                                                  2!             3!
                                     where |x|	 1. We identify x as − jσ/ω  and n as 1/2, and thus

                                                                        1      2
                                                                  σ         σ

                                               jk = jω µ      1 − j  +          +· · · = α + jβ
                                                                 2ω      8 ω
                                     Now, for a good dielectric,

                                                               .             σ      σ  µ
                                                    α = Re( jk) = jω µ     − j   =                  (60a)
                                                                            2ω      2
                                     and

                                                                              1
                                                                 .                σ    2
                                                      β = Im( jk) = ω µ     1 +                     (60b)
                                                                              8 ω
                                     Equations (60a) and (60b) can be compared directly with the transmission line α and
                                     β under low-loss conditions, as expressed in Eqs. (54a) and (55b)in Chapter 10.
                                     In this comparison, we associate σ with G, µ with L, and   with C. Note that in
                                     plane wave propagation in media with no boundaries, there can be no quantity that is
                                     analogous to the transmission line conductor resistance parameter, R.In many cases,
   395   396   397   398   399   400   401   402   403   404   405