Page 401 - Engineering Electromagnetics, 8th Edition
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CHAPTER 11  The Uniform Plane Wave           383

                     the second term in (60b)is small enough, so that

                                                    .
                                                 β = ω µ                             (61)
                     Applying the binomial expansion to (48), we obtain, for a good dielectric

                                          .   µ      3     σ    2  σ
                                       η =       1 −         + j                    (62a)
                                                     8 ω        2ω
                     or


                                               .   µ        σ
                                             η =      1 + j                         (62b)
                                                           2ω
                     The conditions under which these approximations can be used depend on the
                     desired accuracy, measured by how much the results deviate from those given by
                     the exact formulas, (44) and (45). Deviations of no more than a few percent occur if
                     σ/ω  < 0.1.


                                                                                           EXAMPLE 11.5
                     As a comparison, we repeat the computations of Example 11.4, using the approxima-
                     tion formulas (60a), (61), and (62b).
                     Solution. First, the loss tangent in this case is   /  = 7/78 = 0.09. Using (60),


                     with   = σ/ω,wehave


                            . ω       µ  1            12            9  377        −1
                          α =         =   (7 × 8.85 × 10 )(2π × 2.5 × 10 )√  = 21 cm
                                2         2                             78
                     We then have, using (61b),
                                                    √
                                    .
                                                               8
                                                   9
                                  β = (2π × 2.5 × 10 ) 78/(3 × 10 ) = 464 rad/m
                     Finally, with (62b),
                                         . 377          7
                                      η = √      1 + j       = 43 + j1.9
                                             78      2 × 78
                     These results are identical (within the accuracy limitations as determined by the given
                     numbers) to those of Example 11.4. Small deviations will be found, as the reader can
                     verify by repeating the calculations of both examples and expressing the results to four
                     or five significant figures. As we know, this latter practice would not be meaningful
                     because the given parameters were not specified with such accuracy. Such is often the
                     case, since measured values are not always known with high precision. Depending
                     on how precise these values are, one can sometimes use a more relaxed judgment on
                     when the approximation formulas can be used by allowing loss tangent values that
                     can be larger than 0.1 (but still less than 1).
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