Page 53 - Engineering Electromagnetics, 8th Edition
P. 53

CHAPTER 2   Coulomb’s Law and Electric Field Intensity    35

                     Finally,
                                                               0.01
                                               e       e
                                                −2000ρ  −4000ρ
                                 Q =−10  −10 π       −
                                               −2000   −4000   0
                                                1      1      −π
                                 Q =−10  −10 π     −        =     = 0.0785 pC
                                               2000   4000     40
                     where pC indicates picocoulombs.
                         The incremental contribution to the electric field intensity at r produced by an
                     incremental charge  Q at r is

                                             Q      r − r      ρ ν  ν   r − r
                                 E(r) =            2      =            2


                                        4π  0 |r − r | |r − r |  4π  0 |r − r | |r − r |
                     If we sum the contributions of all the volume charge in a given region and let the
                     volume element  ν approach zero as the number of these elements becomes infinite,
                     the summation becomes an integral,
                                                              r − r
                                                    ρ ν (r ) dν
                                        E(r) =               2                       (15)

                                                vol 4π  0 |r − r | |r − r |
                     This is again a triple integral, and (except in Drill Problem 2.4) we shall do our best
                     to avoid actually performing the integration.
                         The significance of the various quantities under the integral sign of (15) might
                     stand a little review. The vector r from the origin locates the field point where E is
                     being determined, whereas the vector r extends from the origin to the source point

                     where ρ v (r )dν is located. The scalar distance between the source point and the


                     field point is |r − r |, and the fraction (r − r )/|r − r | is a unit vector directed from



                     source point to field point. The variables of integration are x , y , and z in rectangular



                     coordinates.
                        D2.4. Calculatethetotalchargewithineachoftheindicatedvolumes:(a)0.1 ≤
                                              1
                        |x|, |y|, |z|≤ 0.2: ρ ν =  ;(b)0 ≤ ρ ≤ 0.1, 0 ≤ φ ≤ π,2 ≤ z ≤ 4; ρ ν =
                                             3 3 3
                                            x y z
                          2 2
                                                         2
                        ρ z sin 0.6φ;(c) universe: ρ ν = e −2r /r .
                        Ans. 0; 1.018 mC; 6.28 C
                     2.4 FIELD OF A LINE CHARGE
                     Up to this point we have considered two types of charge distribution, the point charge
                                                                        3
                     andchargedistributedthroughoutavolumewithadensityρ ν C/m .Ifwenowconsider
                     a filamentlike distribution of volume charge density, such as a charged conductor of
                     very small radius, we find it convenient to treat the charge as a line charge of density
                     ρ L C/m.
                         We assume a straight-line charge extending along the z axis in a cylindrical
                     coordinate system from −∞ to ∞,as shown in Figure 2.6. We desire the electric
                     field intensity E at any and every point resulting from a uniform line charge density ρ L .
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