Page 573 - Engineering Electromagnetics, 8th Edition
P. 573

APPENDIX A   Vector Analysis           555

                     in terms of the component differential lengths, h 1 du, h 2 dν, and h 3 dw,
                                         1 ∂V        1 ∂V        1 ∂V
                                   dV =       h 1 du +    h 2 dν +    h 3 dw
                                        h 1 ∂u      h 2 ∂ν       h 3 ∂w
                     Then, because

                                                             and    dV =∇V · dL
                             dL = h 1 dua u + h 2 dνa ν + h 3 dwa w
                     we see that
                                            1 ∂V      1 ∂V      1 ∂V
                                      ∇V =       a u +     a ν +     a w            (A.3)
                                            h 1 ∂u    h 2 ∂ν    h 3 ∂w
                         ThecomponentsofthecurlofavectorHareobtainedbyconsideringadifferential
                     path first in a u = constant surface and finding the circulation of H about that path,
                     as discussed for rectangular coordinates in Section 7.3. The contribution along the
                     segment in the a ν direction is

                                                    1 ∂
                                          H ν0 h 2 dν −  (H ν h 2 dν)dw
                                                    2 ∂w
                     and that from the oppositely directed segment is
                                                     1 ∂
                                         −H v0 h 2 dν −  (H ν h 2 dν)dw
                                                     2 ∂w
                     The sum of these two parts is
                                                  ∂
                                               −    (H ν h 2 dν)dw
                                                 ∂w
                     or
                                                 ∂
                                               −   (h 2 H ν )dν dw
                                                 ∂w
                     and the sum of the contributions from the other two sides of the path is
                                                ∂
                                                  (h 3 H w )dν dw
                                                ∂ν
                     Adding these two terms and dividing the sum by the enclosed area, h 2 h 3 dν dw,we
                     see that the a u component of curl H is
                                                1     ∂         ∂
                                    (∇× H) u =         (h 3 H w ) −  (h 2 H ν )
                                               h 2 h 3  ∂ν     ∂w
                     and the other two components may be obtained by cyclic permutation. The result is
                     expressible as a determinant,

                                                    a u   a ν   a w


                                                   h 2 h 3  h 3 h 1  h 1 h 2

                                                    ∂     ∂     ∂
                                                                                    (A.4)
                                         ∇× H =

                                                   ∂u    ∂ν     ∂w



                                                  h 1 H u  h 2 H ν  h 3 H w
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